java - 我如何使用通配符在java servlet中映射url

Question

我想实现这个:

http:\\localhost:8080\mysite\search\cotton\search.html
http:\\localhost:8080\mysite\search\bean\search.html
http:\\localhost:8080\mysite\search\cosmetic\search.html
http:\\localhost:8080\mysite\search\shoe\search.html


  <servlet-mapping>
    <servlet-name>abcSearch</servlet-name>
    <url-pattern>/search/*/search.html</url-pattern>
  </servlet-mapping>

表示上述所有网址的一种模式

谁能帮帮我？？？

Answer 1

rules for mappings如下

In the Web application deployment descriptor, the following syntax is used to define mappings:

• A string beginning with a ‘/’ character and ending with a ‘/*’ suffix is used for path mapping.

• A string beginning with a ‘*.’ prefix is used as an extension mapping.

• The empty string ("") is a special URL pattern that exactly maps to the application's context root, i.e., requests of the form http://host:port/<context-root>/. In this case the path info is ’/’ and the servlet path and context path is empty string (““).

• A string containing only the ’/’ character indicates the "default" servlet of the application. In this case the servlet path is the request URI minus the context path and the path info is null.

All other strings are used for exact matches only.

所以这个

/search/*/search.html

完全匹配

http://host/context/search/*/search.html

您无法在 Servlet 的 url-patterns 的路径中间获得路径匹配。

如果您只有 4 条路径，我建议您输入 4 <servlet-mapping>每个精确路径匹配的元素。