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JavaCV cvInRangeS 错误

转载 作者:行者123 更新时间:2023-12-01 13:28:22 26 4
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我正在尝试过滤掉图像中的轮廓。我的代码没有语法错误,但当我运行程序时,我只是得到很多红色文本。我已定位故障点为cvInRangeS。

cvInRangeS(imghsv,minc,maxc,imgbin);

您可以通过 println 语句看到这一点,仅将其设置为“thourgh3”

square.jpg 位于项目目录中,因此如果有帮助的话,这应该不是问题。

控制台返回

Through 1
Through 2
Through 3
OpenCV Error: Assertion failed (src1.size == dst.size && dst.type() == CV_8U) in cvInRangeS, file ..\..\..\..\opencv\modules\core\src\arithm.cpp, line 2972
Exception in thread "main" java.lang.RuntimeException: ..\..\..\..\opencv\modules\core\src\arithm.cpp:2972: error: (-215) src1.size == dst.size && dst.type() == CV_8U in function cvInRangeS

at com.googlecode.javacv.cpp.opencv_core.cvInRangeS(Native Method)
at opencv2.OpenCV2.main(OpenCV2.java:50)
Java Result: 1

完整代码如下

package opencv2; 


/*There are import statments here but for the sake of space I have left them out :D*/

public class OpenCV2 {
public static void main(String[] args) {

IplImage img1;
IplImage imghsv;
IplImage imgbin;
CvScalar minc = cvScalar(95,150,75,0), maxc = cvScalar(145,255,255,0);
CvSeq contour1 = new CvSeq(), contour2;
CvMemStorage storage = CvMemStorage.create();
double areaMax = 1000, areaC = 0;

System.out.println("Through 1");

img1 = cvLoadImage("square.jpg");
imghsv = cvCreateImage(cvGetSize(img1),8,3);
imgbin = cvCreateImage(cvGetSize(img1),8,3);
System.out.println("Through 2");

cvCvtColor(img1,imghsv,CV_BGR2HSV);
System.out.println("Through 3");

cvInRangeS(imghsv,minc,maxc,imgbin);
System.out.println("Through 4");

cvFindContours(imgbin,storage,contour1,Loader.sizeof(CvContour.class),
CV_RETR_LIST, CV_LINK_RUNS,cvPoint(0,0));

contour2 = contour1;

System.out.println("Through 5");

while(contour1 != null && !contour1.isNull()){
areaC = cvContourArea(contour1,CV_WHOLE_SEQ,1);

if(areaC > areaMax){
areaMax = areaC;
}

contour1 = contour1.h_next();
}//end of while

while(contour2 != null && !contour2.isNull()){
areaC = cvContourArea(contour2,CV_WHOLE_SEQ,1);

System.out.println("Through 6");

if(areaC < areaMax){
cvDrawContours(imgbin,contour2,CV_RGB(0,0,0),CV_RGB(0,0,0),
0,CV_FILLED,8,cvPoint(0,0));
}//end of if

System.out.println("Through 7");
contour2 = contour2.h_next();
}//end of while2

System.out.println("Through 8");
cvShowImage("Color",img1);
cvShowImage("CF",img1);
cvWaitKey();

cvReleaseImage(img1);
cvReleaseImage(imghsv);
cvReleaseImage(imgbin);
cvReleaseMemStorage(storage);

}//end of main
}//end of class

最佳答案

cvInRangeS() 假定输入图像的类型为 CV_8U,因此您必须先将其转换。

...
cvtColor(imghsv, grayscale, CV_BGR2GRAY );
cvInRangeS(grayscale,minc,maxc,imgbin);
...

关于JavaCV cvInRangeS 错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21692013/

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