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java - 如何使用字符串标记器和缓冲区。

转载 作者:行者123 更新时间:2023-12-01 13:27:53 24 4
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我正在开发一个程序来反转电话号码,删除所有分隔符,并将其与原始号码进行比较以确定它是否是回文。它还会将电话号码转换为带逗号的整数。我有几个问题。我收到错误,但不知道为什么。此外,它也无法正确判断该数字是否是回文数。任何帮助将不胜感激。

//Phone String Palindrome Conversions
//This program will turn a phone number around and check to see if it is a palindrome
//This program will remove all deasdspace and symbols from the phone number
//This program will reverse the string and compare it to the original
//This program will put a phone number in a long intiger format
import java.io.*;
import java.util.*;
import java.text.DecimalFormat;
public class DottinoN_palindrome
{
public static void main (String [] args) throws IOException
{
String phoneshort1;
boolean pal;
BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
System.out.println("Please enter your phone number");
String phone1=br.readLine();
phoneshort1 = spaceremover(phone1);
System.out.println(phoneshort1);
pal = palindrometest(phoneshort1);
System.out.println(pal);
if(pal = false)
{
System.out.println("Your phone number is a palindrome!");
}
else if(pal = true)
System.out.println("Your phone number is not a palendrome...");
numberformat(phoneshort1);

}
public static String spaceremover (String phone2)
{
String phoneshort = "";
StringTokenizer st = new StringTokenizer(phone2,"()- " ,false);
while(st.hasMoreTokens())
{
phoneshort += st.nextToken();
}
return phoneshort;
}
public static boolean palindrometest (String phoneshort2)
{
boolean pal;
StringBuffer br = new StringBuffer(phoneshort2);
String phonebkwd = br.reverse().toString();
if(phonebkwd == phoneshort2)
{
pal = true;
}
else pal = false;
System.out.println(phonebkwd + "--" + phoneshort2);
return pal;

}
public static void numberformat (String phoneshort2)
{
DecimalFormat formatter = new DecimalFormat("0,000,000,000");
int number = Integer.parseInt(phoneshort2);
System.out.println("Your phone number as an intiger is: " + formatter.format(number) );
}
}

最佳答案

你的程序确实存在一些问题,

  1. 如wipindipy10所说,用equal方法改变字符串比较

  2. 如果打印条件是否为回文,则改为该值

    if (!pal) {
    System.out.println("Your phone number is a palindrome!");
    } else {
    System.out.println("Your phone number is not a palendrome...");
    }
  3. 正如您提到的,异常发生在底部附近。这可能是您输入的电话超出了Integer.MAX_VALUE,即2147483647 [0x7fffffff]

关于java - 如何使用字符串标记器和缓冲区。,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21717104/

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