java - 如何选择要复制的文件？

Question

我得到了这个代码，将文件从App目录复制到SD卡上的文件夹，并使用该文件设置为铃声。但有件事我不明白。我如何确定要获取哪个文件？假设我在 raw 文件夹中有 1 个名为 fusrodah 的文件。如何让我的应用程序选择该文件并将其复制到 sdcard 文件夹？

private int size;

private static final int BUFFER_LEN = 1024;


private void copyFile(AssetManager assetManager, String fileName, File out) throws FileNotFoundException, IOException {
    size = 0;
    FileOutputStream fos = new FileOutputStream(out);
    InputStream is = assetManager.open(fileName);       
    int read = 0;
    byte[] buffer = new byte[BUFFER_LEN];
     while ((read = is.read(buffer, 0, BUFFER_LEN)) >= 0) {
            fos.write(buffer, 0, read);
            size += read;
      }
    fos.flush();    
    fos.close();
    is.close();
}
public void onClick(View arg0) {        
    AssetManager assetManager = getAssets();

    File file = new File(Environment.getExternalStorageDirectory(),
            "/myRingtonFolder/Audio/");
    if (!file.exists()) {
        file.mkdirs();
    }

    String path = Environment.getExternalStorageDirectory()
            .getAbsolutePath() + "/myRingtonFolder/Audio/";

    File out = new File(path + "/", "fusrodah.mp3");     
    if(!out.exists()){
        try {
            copyFile(assetManager, "fusrodah.mp3", out);
        } catch (FileNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

Answer 1

替换这个

InputStream is = assetManager.open(fileName);       

与

 InputStream is = getResources().openRawResource(R.raw.fusrodah);