java - 如何为循环中的对象提供新名称？

Question

所以我有一个名为 PlayingCard 的类，它创建一个包含 int 等级和 int 花色的对象(以模拟扑克牌)。

public class PlayingCard 
{
private int rank;
private int suit;


public PlayingCard(int rank1, int suit1) //PlayingCard Constructor
{
    rank = rank1;
    suit = suit1;
}


public int getRank() //Get method to retrieve value of card Rank
{
   if(rank >0 && rank <15)
   {
       return rank;
   }
   else
       return 0;
}


public String getSuit() //Get method to retrieve value of card Suite
{

    while (suit >0 && suit <5)
    {
        if (suit == 1)
        {
            return "Clubs";
        }
        else if (suit == 2)
        {
            return "Diamonds";
        }
        else if (suit == 3)
        {
            return "Hearts";
        }
        else
        {
            return "Spades";
        }
    }

    return "Invalid suit";
}


@Override //Overrides default Java toString method
public String toString()
{
    String strSuit = "";

    switch(suit) 
    {
        case 1: strSuit = "Clubs";
            break;
        case 2: strSuit = "Diamonds";
            break;
        case 3: strSuit = "Hearts";
            break;
        case 4: strSuit = "Spades";
            break;
        default: strSuit = "Invalid Suit";
            break;
    }

    String output = getClass().getName() + "[suit = " +strSuit + ", rank = "
                    +rank + "]";

    return output;
}


public String format() //Allows individual cards to be displayed in a
{                     //Specific format.
    String strSuit = "";

    switch(suit) 
    {
        case 1: strSuit = "Clubs";
            break;
        case 2: strSuit = "Diamonds";
            break;
        case 3: strSuit = "Hearts";
            break;
        case 4: strSuit = "Spades";
            break;
        default: strSuit = "Invalid Suit";
            break;
    }

    return rank + " of " + strSuit + ", ";
}

@Override
public boolean equals(Object y) //Method for evaluating Object equality.
{

    if (getClass() != y.getClass()) //Checks if both object are from the
    {                              //Same class.
        return false;
    }

    if (y == null) //Checks if second object is empty or non-existent.
    {
        return false;
    }

    PlayingCard other = (PlayingCard) y;
    return rank == other.rank && suit == other.suit;
}
}

然后我需要创建一个名为 PackBuilder 的程序，它应该使用我的类模拟构建一副纸牌。

问题是我不确定如何为每个对象指定新名称。我想到了类似的数组:

while(rank < 15)
        {
            PlayingCard cardDeck[1] = new PlayingCard(rank, suit);
        }

但它说 cardDeck 已经定义了(我不确定我是否可能做错了，或者使用数组是否不起作用)

我想要的命名方案就像“card1”“card2”“card3”等等，直到我有 52 张牌，每张牌都有自己的花色/等级组合来创建一副牌。

Answer 1

您正在尝试将 PlayingCard 分配给 cardDeck 数组中的第二个元素(索引 1)，每次。此外，cardDeck 数组在 while 循环的每次迭代底部立即被丢弃。它的作用域仅存在于循环内部。

改变这个

while(rank < 15)
    {
        PlayingCard cardDeck[1] = new PlayingCard(rank, suit);
    }

像这样的事情

PlayingCard[] cardDeck = new PlayingCard[52];

int i = 0;
while(rank < 15)
    {
        cardDeck[i++] = new PlayingCard(rank, suit);
    }

为了避免无限循环，请更改

cardDeck[i++] = new PlayingCard(rank, suit);

至

cardDeck[i++] = new PlayingCard(rank++, suit);

可能还有其他问题，但这是一个很好的开始。