java - 必需的 String[] 找到 String Java

Question

我试图循环遍历字节数组并将其解码为字符串，使用 RSA 加密，加密无需数组即可工作，但我试图通过加密字符串的每个单词来使其可用于更长的数据，但是执行此操作时，我收到错误 required String[] found String Java。

 // Decrypt the cipher text using the private key.
        inputStream = new ObjectInputStream(new FileInputStream(PRIVATE_KEY_FILE));
        final PrivateKey privateKey = (PrivateKey) inputStream.readObject();
        String[][] decryptedText = new String[cipherText.length][];
        for (int i = 0; i < cipherText.length; i++) {
            **ERROR ON THIS LINE - required String[] found String Java**
         decryptedText[i] = decrypt(cipherText[i], privateKey);

        }

解密方法

  public static String decrypt(byte[] text, PrivateKey key) {
    byte[] dectyptedText = null;
    try {
        // get an RSA cipher object and print the provider
        final Cipher cipher = Cipher.getInstance(ALGORITHM);
        // decrypt the text using the private key
        cipher.init(Cipher.DECRYPT_MODE, key);
        dectyptedText = cipher.doFinal(text);

    } catch (InvalidKeyException | NoSuchAlgorithmException | BadPaddingException |IllegalBlockSizeException | NoSuchPaddingException ex) {
    }

    return new String(dectyptedText);
}

加密方法

public static byte[] encrypt(String text, PublicKey key) {
    byte[] cipherText = null;
    try {
        // get an RSA cipher object and print the provider
        final Cipher cipher = Cipher.getInstance(ALGORITHM);
        // encrypt the plain text using the public key
        cipher.init(Cipher.ENCRYPT_MODE, key);
        cipherText = cipher.doFinal(text.getBytes());
    } catch (InvalidKeyException | NoSuchAlgorithmException | BadPaddingException | IllegalBlockSizeException | NoSuchPaddingException e) {
    }
    return cipherText;
}

Answer 1

问题是你的decryptedText是一个二维数组

 String[][] decryptedText = new String[cipherText.length][];

所以这一行

decryptedText[i] = decrypt(cipherText[i], privateKey);

必须将一个数组放入decryptedText。您可以更改 decryptedText 的声明来解决此问题

String[] decryptedText = new String[cipherText.length];

希望这有帮助。