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java - 对字符串列表进行排序

转载 作者:行者123 更新时间:2023-12-01 13:17:44 25 4
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我被分配了这个任务:

Complete the function void sort(List l) that sorts a list l that contains the strings "one","two","three","four" (although not necessarily in that order). You should declare a Comparator, and use this with the Collections.sort function. The comparator should use the comp function described above. The list l will be altered when it is sorted.

我已经编写的代码是这样的:

import java.util.*;

public class CW3 {

private static HashMap < String, Integer > map = new HashMap < String, Integer > ();

public CW3() {
map.put("one", 1);
map.put("two", 2);
map.put("three", 3);
map.put("four", 4);

List listB = Arrays.asList("A", "B", "C");
}

public static void main(String[] args) {
System.out.println(new CW3().comp("one", "two"));
System.out.println(new CW3().comp("two", "one"));
System.out.println(new CW3().comp("one", "one"));
}

int comp(String s1, String s2) {
int i1 = map.get(s1);
int i2 = map.get(s2);
return (i1 < i2 ? -1 : (i1 == i2 ? 0 : 1));
}

void sort(List l) {
Comparator c = new Comparator() {

public int compare(Object o1, Object o2) {
return 0; // FIXME change this so it calls comp
}
};
// now sort l using the comparator c
// FIXME complete this line
}

有什么想法从哪里开始吗?它说列表,所以我必须创建一个列表,但是我该如何对它们进行排序?

最佳答案

您需要做的是定义 compare方法。它应该需要两个对象 o1o2作为参数并返回

  • -1o1 < o2
  • 0o1 == o2
  • 1o1 > o2

您的Comparator使用此方法作为决定元素顺序的基础。然后对列表进行排序 l通过调用 Collections.sort(l, c) ,其中cComparator你已经定义了。

关于java - 对字符串列表进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22332489/

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