php - 在 Laravel 中将用户播种到数据库的问题

Question

我正在尝试在数据库中播种用户，但出现错误提示

Symfony\Component\Debug\Exception\FatalThrowableError  : Call to a member function random() on bool

我有用户表和性别表，在用户表中带有gender_id，指向具有hasMany关系的性别表中的男人或女人列。当我播种数据库并创建新用户时，我希望能够在用户表中自动写入gender_id。目前，使用此代码，我从上面得到该错误，并在gender_id 列中得到 NULL，但它在用户和性别表中正确插入。当我删除 random() 函数时，它总是在性别 ID 中插入 1，但我希望能够随机写入 1 或 2。此外，当我转储 $genders 时，它返回 TRUE。有没有办法解决这个问题，任何帮助表示赞赏。这是我的代码。

UserSeeder.php

<?php

use Carbon\Carbon;
use Illuminate\Database\Seeder;
use Illuminate\Support\Facades\DB;
use Illuminate\Support\Facades\Hash;

class UsersTableSeeder extends Seeder
{
    /**
    * Run the database seeds.
    *
    * @return void
    */
    public function run()
    {
        $genders = DB::table('genders')->insert([
            [
                'genders' => 'Woman',
            ],
            [
                'genders' => 'Woman Looking For Woman',
            ],
            [
                'genders' => 'Man',
            ]
        ]);

        //dd($genders);

        DB::table('users')->insert([
            'gender_id' => $genders->random(),
            'name' => 'authuser',
            'email' => 'authuser@auth.com',
            'email_verified_at' => now(),
            'password' => Hash::make('auth123456'),
            'age' => 18,
            'remember_token' => Str::random(10), 
            'created_at' => Carbon::now(),
            'updated_at' => Carbon::now(),
        ]); 
    }
}

用户表

<?php

use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;

class CreateUsersTable extends Migration
{
    /**
    * Run the migrations.
    *
    * @return void
    */
    public function up()
    {
        Schema::create('users', function (Blueprint $table) {
            $table->bigIncrements('id');
            $table->unsignedBigInteger('gender_id')->nullable();
            $table->string('name');
            $table->string('email')->unique();
            $table->timestamp('email_verified_at')->nullable();
            $table->string('password')->default();
            $table->integer('age')->default()->nullable();
            $table->rememberToken();
            $table->timestamps();
        });
    }

    /**
    * Reverse the migrations.
    *
    * @return void
    */
    public function down()
    {
        Schema::dropIfExists('users');
    }
}

性别表

<?php

use Illuminate\Database\Migrations\Migration;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Support\Facades\Schema;

class CreateGendersTable extends Migration
{
    /**
    * Run the migrations.
    *
    * @return void
    */
    public function up()
    {
        Schema::create('genders', function (Blueprint $table) {
            $table->bigIncrements('id');
            $table->string('genders');
        });
    }

    /**
    * Reverse the migrations.
    *
    * @return void
    */
    public function down()
    {
        Schema::dropIfExists('genders');
    }
}

用户名

public function gender()
{
    return $this->belongsTo(Gender::class, 'gender_id', 'id');
}

性别.php

public function users()
{
    return $this->hasMany(User::class, 'gender_id', 'id');
}

Answer 1

您可以从 Gendre 中提取您的 id 值并像这样随机地做:

$genders = DB::table('genders')->insert([
            ['genders' => 'Woman'],
            ['genders' => 'Woman Looking For Woman'],
            ['genders' => 'Man']
        ]);
$gendreIds = Genders::pluck('id');

DB::table('users')->insert([
            'gender_id' => $gendreIds->random(),
            ...
]); 

这将为您提供数据库中存在的性别。

有时种子不会给你从 1 到 3 的 ID。

所以我认为使用 rand(1,3) 不是最好的解决方案.

祝你好运!