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Java Android方法需要很长时间才能执行?

转载 作者:行者123 更新时间:2023-12-01 13:11:49 24 4
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我正在创建一个非常简单的应用程序,按下时将图片颜色更改为棕褐色滤镜。当我运行该应用程序时,一切正常,但图像需要近一分钟才能改变。您能快速浏览一下我的代码并看看您能否告诉我原因吗?

public class Pictue extends ActionBarActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_pictue);
ImageButton button = (ImageButton) findViewById(R.id.imageButton1);
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Bitmap b1 = BitmapFactory.decodeResource(getResources(), R.drawable.chin);
b1 = createSepiaToningEffect(b1,10,7.00,6.00,3.00);
ImageView chin = (ImageView) findViewById(R.id.imageView1) ;
chin.setImageBitmap(b1);
}
});
}

public static Bitmap createSepiaToningEffect(Bitmap src, int depth, double red, double green, double blue) {
int width = src.getWidth();
int height = src.getHeight();
Bitmap bmOut = Bitmap.createBitmap(width, height, src.getConfig());
final double GS_RED = 0.3;
final double GS_GREEN = 0.59;
final double GS_BLUE = 0.11;
int A, R, G, B;
int pixel;

for(int x = 0; x < width; ++x) {
for(int y = 0; y < height; ++y) {
pixel = src.getPixel(x, y);
A = Color.alpha(pixel);
R = Color.red(pixel);
G = Color.green(pixel);
B = Color.blue(pixel);
B = G = R = (int)(GS_RED * R + GS_GREEN * G + GS_BLUE * B);

// apply intensity level for sepid-toning on each channel
R += (depth * red);
if(R > 255) { R = 255; }

G += (depth * green);
if(G > 255) { G = 255; }

B += (depth * blue);
if(B > 255) { B = 255; }

bmOut.setPixel(x, y, Color.argb(A, R, G, B));
}
}

return bmOut;
}
}

最佳答案

关于Java Android方法需要很长时间才能执行?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22797835/

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