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java - 在java中求矩阵的平均值

转载 作者:行者123 更新时间:2023-12-01 13:07:07 25 4
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如何找到 2D 矩阵(5×5)中每 8 个元素的平均值并将其替换为元素号(9)?

Java 编程(OOP)

第一个代码应该像 this 例如:

img
(来源:0zz0.com)

最佳答案

所以我这样做只是为了好玩,这是我的代码。它适用于任何大小的矩阵。

public class Matrixer
{

final double[][] matrix, computedMatrix;
final int rows, cols;

public Matrixer(int N, int M, final double[][] imatrix)
{
rows = N;
cols = M;
matrix = imatrix;
computedMatrix = new double[N][M];
}

public void computeAverages()
{
for (int i = 1; i < rows - 1; i++)
{
for (int j = 1; j < cols - 1; j++)
{
computedMatrix[i][j] = cellNeighborsAverage(i, j);
}
}
}

private double cellNeighborsAverage(int row, int col)
{
// Ignore center cell
double sum = matrix[row - 1][col - 1] + matrix[row - 1][col]
+ matrix[row - 1][col + 1] + matrix[row][col - 1]
+ matrix[row][col + 1] + matrix[row + 1][col - 1]
+ matrix[row + 1][col] + matrix[row + 1][col + 1];
return sum / 8;
}

public void printComputedMatrix()
{
for (int i = 0; i < rows; i++)
{
for (int j = 0; j < cols; j++)
{
System.out.printf("%.2f", computedMatrix[i][j]);
System.out.print(", ");
}
System.out.println();
}
}

public static void main(String[] args)
{
final double[][] matrix =
{
{1, 2, 3, 4, 5},
{5, 4, 3, 5, 1},
{3, 2, 2, 3, 4},
{2, 3, 4, 5, 3},
{3, 2, 4, 5, 6},
};

Matrixer mx = new Matrixer(5, 5, matrix);
mx.computeAverages();
mx.printComputedMatrix();
}
}

测试输出:

0.00, 0.00, 0.00, 0.00, 0.00, 
0.00, 2.63, 3.13, 3.13, 0.00,
0.00, 3.25, 3.63, 3.38, 0.00,
0.00, 2.75, 3.25, 3.88, 0.00,
0.00, 0.00, 0.00, 0.00, 0.00

关于java - 在java中求矩阵的平均值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23184503/

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