java - 在 Java 中使用 toString 打印 Long 值

Question

我有一个关于使用 toString 方法打印长值的问题。

我的代码是:

public class LinkedLargeInteger {

    private class Node {

    private int data;
    private long dat;
    private Node next;

    private Node(int data, Node next) {
        this.data = data;
        this.next = next;
    }

    private Node(int data) {
        this(data, null);
    }

    private Node() {
        data = 0;
        next = null;
    }

    private Node(long dat, Node next) {
        this.dat = dat;
        this.next = next;
    }

    private Node(long dat) {
        this(dat, null);
    }

}

private Node head;
private Node tail;
private int size;
private String largeString;
private int largeInt;
private long largeLong;

public LinkedLargeInteger(long largeLong) {
    String s = Long.toString(largeLong);
    head = new Node();
    tail = head;
    size = 0;
    for (int i = 0; i < s.length(); i++) {
        tail.next = new Node(Long.parseLong(s), null);
        tail = tail.next;
        size++;
    }
}

@Override
public String toString() {
    StringBuilder builder = new StringBuilder();
    Node current = head.next;
    for (int i = 0; i < this.size; i++) {
        builder.append(i + 1);
        current = current.next;
    }
    return builder.toString();
}

public static void main(String[] args) {
    LinkedLargeInteger numLong = new LinkedLargeInteger(100000000000L);
    System.out.println(numLong);
}
}

我已经用我的 Node 类实现了一个链表，并想用我的构造函数打印出一个长值。当我在 main 中打印一个长值时，它给出的数字与我作为参数输入的数字完全不同。有人知道我的问题可能是什么吗？

Answer 1

尝试修复构造函数:

public LinkedLargeInteger(long largeLong) {
    String s = Long.toString(largeLong);
    head = new Node();
    tail = head;
    size = 0;
    for (int i = 0; i < s.length(); i++) {
    // You were putting the whole number, not the digits
        tail.next = new Node(Long.parseLong(String.valueOf(s.charAt(i))), null); // <<==
        tail = tail.next;
        size++;
    }
}

还有 toString:

public String toString() {
StringBuilder builder = new StringBuilder();
    Node current = head.next;
    for (int i = 0; i < this.size; i++) {
        builder.append(current.dat); // <<==
        current = current.next;
    }
    return builder.toString();
}