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java - Compiling Issues,说是非法启动和期待;在两个构造函数上

转载 作者:行者123 更新时间:2023-12-01 13:03:27 26 4
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错误:';'预计
表达式非法开始

这是我在 getGrid 和 checkGrid 程序中遇到的两个错误似乎无法弄清楚问题是什么以及造成问题的原因。帮助将不胜感激

import java.util.Scanner;

public class Aleko_SudokuChecker
{

public static void main(String[] args)
{
Scanner in = new Scanner(System.in);

System.out.print("\nWelcome to the Sudoku Checker v1.0!\n");
System.out.print("\nThis program checks simple, small, 4x4 Sudoku grids for\n");
System.out.print("correctness. Each column, row and 2x2 region contains the numbers\n");
System.out.print("1 through 4 only once.\n\n");
System.out.print("To check your sudoku, enter your board one row at a time, with\neach digit separated by a space. Hit ENTER at the end of a row.\n");
SudokuChecker foo = new SudokuChecker();
foo.getGrid();
foo.checkGrid();


public void getGrid()
{

System.out.print("\nEnter Row 1: ");
int i = in.nextInt();
int j = in.nextInt();
int k = in.nextInt();
int m = in.nextInt();

System.out.print("Enter Row 2: ");
int n = in.nextInt();
int i1 = in.nextInt();
int i2 = in.nextInt();
int i3 = in.nextInt();

System.out.print("Enter Row 3: ");
int i4 = in.nextInt();
int i5 = in.nextInt();
int i6 = in.nextInt();
int i7 = in.nextInt();

System.out.print("Enter Row 4: ");
int i8 = in.nextInt();
int i9 = in.nextInt();
int i10 = in.nextInt();
int i11 = in.nextInt();
}



public void checkGrid()
{
System.out.print("\nThank you. Now checking ... \n");

int x = 0;



int i12 = i + j + n + i1;
int i13 = i4 + i5 + i8 + i9;
int i14 = k + m + i2 + i3;
int i15 = i6 + i7 + i10 + i11;

int i16 = i + j + k + m;
int i17 = n + i1 + i2 + i3;
int i18 = i4 + i5 + i6 + i7;
int i19 = i8 + i9 + i10 + i11;

int i20 = i + n + i4 + i8;
int i21 = j + i1 + i5 + i9;
int i22 = k + i2 + i6 + i10;
int i23 = m + i3 + i7 + i11;
if (i12 == 10)
{
System.out.print("\nREG-1:PASS");
}
else
{
System.out.print("\nREG-1:FAIL");
x = x+1;
}
if (i13 == 10)
{
System.out.print("\nREG-2:PASS");
}
else
{
System.out.print("\nReg-2:FAIL");
x = x +1;
}
if (i14 == 10)
{
System.out.print("\nREG-3:PASS");
}
else
{
System.out.print("\nREG-3:FAIL");
x = x+1;
}
if (i15 == 10)
{
System.out.print("\nREG-4:PASS\n");
}
else
{
System.out.print("\nREG-4:FAIL\n");
x = x+1;
}
if (i16 == 10)
{
System.out.print("\nROW-1:PASS");
}
else
{
System.out.print("\nROW-1:FAIL");
x = x+1;
}
if (i17 == 10)
{
System.out.print("\nROW-2:PASS");
}
else
{
System.out.print("\nROW-2:FAIL");
x = x+1;
}
if(i18 == 10)
{
System.out.print("\nROW-3:PASS");
}
else
{
System.out.print("\nROW-3:FAIL");
x = x+1;
}
if (i19 == 10)
{
System.out.print("\nROW-4:PASS\n");

}
else
{
System.out.print("\nROW-4:FAIL\n");
x = x+1;
}
if (i20 == 10)
{
System.out.print("\nCOL-1:PASS");
}
else
{
System.out.print("\nCOL-1:FAIL");
x = x+1;
}
if (i21 == 10)
{
System.out.print("\nCOL-2:PASS");
}
else
{
System.out.print("\nCOL-2:FAIL");
x = x+1;
}
if (i22 == 10)
{
System.out.print("\nCOL-3:PASS");
}
else
{
System.out.print("\nCOL-3:FAIL");
x = x+1;
}
if (i23 == 10)
{
System.out.print("\nCOL-4:PASS\n");
}
else
{
System.out.print("\nCOL-4:FAIL\n");
x = x+1;
}
if ((i12 == 10) && (i13 == 10) && (i14 == 10) && (i15 == 10) && (i16 == 10) && (i17 == 10) && (i18 == 10) && (i19 == 10) && (i20 == 10) && (i21 == 10) && (i22 == 10) && (i23 == 10)) {
System.out.print("\nCongratulations!\nThis Sudoku is valid.\n\n");
}
else
{
System.out.print("\nSorry.\nThis Sudoku is invalid.\n\n");
}
}


}
}

最佳答案

我认为您需要在 foo.checkGrid(); 之后以及开始新方法之前使用大括号“}”关闭 main() 方法 public void getGrid().

关于java - Compiling Issues,说是非法启动和期待;在两个构造函数上,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23378965/

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