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java - 如何在二叉搜索树中找到最大对象

转载 作者:行者123 更新时间:2023-12-01 12:59:25 25 4
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嗨,我为 BST 构建了这段代码: 公共(public)类 BinarySearchTreeCode {

private class BSTNode {
public Object data;
public BSTNode left;
public BSTNode right;
BSTNode(Object newdata) {
data = newdata;
left = null;
right = null;
}
BSTNode(Object data, BSTNode left, BSTNode right){
this.data = data;
this.left = left;
this.right = right;
}
public String toString(){
return "data: "+data+" ";
}
}


// tree root
private BSTNode root;

public BinarySearchTreeCode(){
root = null;

}
public BinarySearchTreeCode(BSTNode n){
root = n;
}

public BinarySearchTreeCode(BinarySearchTreeCode bst){// copy constructor
this.root = clone(bst.root);
}
BSTNode clone(final BSTNode source){
if (source == null) return null;
else
return new BSTNode(source.data, clone(source.left), clone(source.right));
}

// compare two objects (integer type)
private static int compare(Object o1, Object o2) {
int ans = 0;
int n1 = (Integer)o1;
int n2 = (Integer)o2;
if(n1>n2) ans = 1;
else if(n1<n2) ans = -1;
return ans;
}

// insert element to the tree
public void insertRecurs(Object elem) {
root = insertRecurs(root, elem);
}
BSTNode insertRecurs(BSTNode node, Object elem) {
if (node == null) {

return new BSTNode(elem);
}
if (compare(elem, node.data) < 0) {
node.left = insertRecurs(node.left, elem);
return node;
}
else{
node.right = insertRecurs(node.right, elem);
return node;
}
}

// search for element elem
public boolean find(Object elem) {
return find(root,elem);
}
boolean find(BSTNode tree, Object elem) {
if (tree == null)
return false;
if (compare(elem, tree.data) == 0)
return true;
if (compare(elem, tree.data) < 0)
return find(tree.left, elem);
else
return find(tree.right, elem);
}

// print all tree nodes
public void print() {
print(" ",root);
System.out.println();
}
void print(String s,BSTNode tree) {//Inorder
if (tree != null) {
print(s+"L ,",tree.left);
System.out.println(tree.data+" : "+s);
print(s+"R ,",tree.right);
}
}
///////////////////////////
public void remove(Object elem) {
root = remove(root, elem);
}
public static BSTNode remove(BSTNode node, Object n){
if(node != null){
if(compare(n,node.data) > 0){
node.right = remove(node.right,n);
}
else if(compare(n,node.data) < 0){
node.left = remove(node.left,n);
}
else{//the node that should be deleted is found
if(node.left == null && node.right == null){
node = null;
}
else if(node.left != null && node.right == null){//the node has only one child (left)
node = node.left;
}
else if(node.right != null && node.left == null){//the node has only one child (right)
node = node.right;
}
else{//node "tree" has two children
if(node.right.left == null){// his right node has only one child (right)
node.right.left = node.left;
node = node.right;
}
else{// remove the smallest element
BSTNode q, p = node.right;
while(p.left.left != null)
p = p.left;
q = p.left;
p.left = q.right;
node.data = q.data;
}
}
}
}
return node;
}
public void insertLoop(Object elem) {
BSTNode newNode = new BSTNode(elem);
if (root == null){
root = newNode;
}
else{
BSTNode n = root;
boolean flag = true;
while (flag){
if (compare(elem,n.data) > 0){
if (n.right != null) n = n.right;
else{
n.right = newNode;
flag = false;;
}
}
else{
if (n.left != null) n = n.left;
else{
n.left = newNode;
flag = false;;
}
}
}

}
}
public boolean isEmpty(){
return this.root == null;
}

//代码结束

问题是我如何构建一个函数来给出 BNT 中的最大对象,如下所示

公共(public)对象最大值(){

}

有什么建议吗?

感谢您的帮助。

最佳答案

二叉搜索树中的最大对象是最右边的节点。您可以通过以下方式获取:

1)从根节点开始

2)检查node.right是否为空

3) 如果是,则节点是最大对象。终止搜索。

4) 如果没有,则移动到最右边的 nde (node = node.right) 并重复步骤 2。

示例代码:

public BSTNode  findMaxNode()
{
Node temp = root;
Node max = null;
while(temp != null)
{
max = temp;
temp = temp.right
}

return max;
}

关于java - 如何在二叉搜索树中找到最大对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23640457/

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