java - java HTTP post 中的 HTTP/1.1 400 错误请求

Question

我正在尝试使用带有凭据的 HTTP post 方法将 xml 数据发布到 API，但出现 HTTP/1.1 400 Bad Request 错误..任何人都可以帮助我......

这是我的示例代码:

BufferedReader br = new BufferedReader(new FileReader(new File("Data.xml")));

        StringBuilder sb = new StringBuilder();

        while((line=br.readLine())!= null){
            sb.append(line.trim());
            }
        System.out.println("xml:  "+sb);



        params=sb.toString();
        HttpPost request = new HttpPost("*****************url***************");
        String urlaparam=URLEncoder.encode("importFormatCode:1&data:"+params,"UTF-8");
        String userCredentials = "****:******";
        byte[] auth = Base64.encodeBase64(userCredentials.getBytes());

        StringEntity entity=new StringEntity(urlaparam);
        request.addHeader("Content-type","application/x-www-form-urlencoded");
        request.addHeader("Accept", "application/xml");
        request.addHeader("Accept-Language", "en-US,en;q=0.5");
        request.addHeader("Authorization", "Basic " + new String(auth));


        request.setEntity(entity);
        HttpResponse response = httpClient.execute(request);    

       System.out.println(response.getStatusLine());
       System.out.println(request);
}
    catch(Exception e)
{
}

Answer 1

首先，您的表单参数编码不正确。您使用冒号 (:) 将键与其值分开，但必须使用等号 (=):

• 错误:“importFormatCode:1&data:”+ params
• 正确:"importFormatCode=1&data="+ params

(另请参阅 W3C.org - Forms in HTML Documents - application/x-www-form-urlencoded )

除此之外，您不能对整个字符串进行 URL 编码，而只能对键和值进行 URL 编码。否则，您还将对分隔符 = 和 &!

进行编码

最简单的方法是使用现有的实用程序类org.apache.http.client.utils.URLEncodedUtils(假设您使用的是 Apache HTTP Components ):

String xmlData = // your xml data from somewhere

List<NameValuePair> params = Arrays.asList(
    new BasicNameValuePair("importFormatCode", "1"),
    new BasicNameValuePair("data", xmlData)
);
String body = URLEncodedUtils.format(params, encoding); // use encoding of request

StringEntity entity = new StringEntity(body);
// rest of your code