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r - ggplot2:在 ROC 图上使用 scale_x_reverse

转载 作者:行者123 更新时间:2023-12-01 12:50:16 25 4
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我尝试使用 ggplot2pRoc 包中的 plot.roc 函数重现 ROC 曲线。

library(mlbench)
library(caret)

data(Sonar)

set.seed(998)
fitControl <- trainControl(method = "repeatedcv",
number = 10,
repeats = 10,
## Estimate class probabilities
classProbs = TRUE,
## Evaluate performance using
## the following function
summaryFunction = twoClassSummary)

gbmGrid <- expand.grid(interaction.depth = c(1, 5, 9),
n.trees = (1:30)*50,
shrinkage = 0.1,
n.minobsinnode = 20)

inTraining <- createDataPartition(Sonar$Class, p = .75, list = FALSE)
training <- Sonar[ inTraining,]
testing <- Sonar[-inTraining,]


set.seed(825)
gbmFit <- train(Class ~ ., data = training,
method = "gbm",
trControl = fitControl,
verbose = FALSE,
tuneGrid = gbmGrid,
## Specify which metric to optimize
metric = "ROC")
gbmFit

probs = predict(gbmFit, newdata = testing, type = "prob")

roc = roc(predictor = probs$M,
response = testing$Class,
levels = c('M','R'),
percent = TRUE)
plot.roc(roc, print.auc = TRUE, col='red')


df = data.frame(Specificity=roc$specificities, Sensitivity=roc$sensitivities)
ggplot(data = df, aes(x = Specificity, y = Sensitivity))+
geom_step(color='red', size=2, direction = "hv")+
scale_x_reverse()+
geom_abline(intercept = 100, slope = 1, color='grey')+
annotate("text", x = 30, y = 20, label = paste0('AUC: ', round(roc$auc,1), '%'), size = 8)+
ylab('Sensitivity (%)')+
xlab('Specificity (%)')

plot.roc 产生: plot.roc

ggplot2 产生: ggplot2

scale_x_reverse() 似乎是问题所在,是否有任何其他方法可以反转 X 轴或更正该图?

最佳答案

您可以使用geom_path 代替geom_step:

ggplot(data = df, aes(x = Specificity, y = Sensitivity))+
geom_path(colour = 'red', size = 2)+
scale_x_reverse() +
geom_abline(intercept = 100, slope = 1, color='grey')+
annotate("text", x = 30, y = 20, label = paste0('AUC: ', round(roc$auc,1), '%'), size = 8)+
ylab('Sensitivity (%)')+
xlab('Specificity (%)')

enter image description here

关于r - ggplot2:在 ROC 图上使用 scale_x_reverse,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37438461/

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