oracle - PL/SQL 和日期间隔

Question

我有一个日期，我想打印该日期的偏移量。我可以这样做:

dbms_output.put_line(to_char(g_startDate - interval '4' month ,'YYYY-MM-DD'));

而且效果很好。问题是间隔是可变的。当我尝试这个时:

dbms_output.put_line(to_char(g_startDate - interval g_dateOffsetAmt month ,'YYYY-MM-DD'));

我收到一个编译器错误。

我认为这可能是因为 g_dateOffsetAmt 是一个 integer 所以我尝试了这个:

dbms_output.put_line(to_char(g_startDate - interval to_char(g_dateOffsetAmt) month ,'YYYY-MM-DD'));

尽管我仍然收到编译器错误提示:

Error: PLS-00103: Encountered the symbol "TO_CHAR" when expecting one of the following:          . ) , * @ & | = - +  at in is mod remainder not rem =>          ..   or != or ~= >=  and or like          LIKE2_ LIKE4_ LIKEC_ as between from using || member           SUBMULTISET_       The symbol "," was substituted for "TO_CHAR" to continue.Line: 704Error: PLS-00103: Encountered the symbol "MONTH" when expecting one of the following:          . ( ) , * % & | = - +  at in is mod remainder not range          rem => ..   or != or ~= >=  and or          like LIKE2_ LIKE4_ LIKEC_ between || multiset member          SUBMULTISET_       The symbol "." was substituted for "MONTH" to continue.Line: 704

还有其他方法吗？

Answer 1

您可能想使用 NumToYMInterval 函数

declare
  v_interval pls_integer := 4;
begin
  dbms_output.put_line( sysdate - NumToYMInterval( v_interval, 'month' ) );
end;
/