java - 检测 Flappy Bird 克隆中特定区域的触摸

Question

所以，我正在制作一只飞翔的小鸟克隆。问题是我是使用 java 和 libgdx 编程的新手，我想请求您的帮助。我想在特定区域(只是一个简单的矩形形状)进行触摸检测，而不是在整个屏幕上单击。

这是我当前来自 InputHandler 类的代码:

public class InputHandler implements InputProcessor {
private Bird myBird;
private GameWorld myWorld;

// Ask for a reference to the Bird when InputHandler is created.
public InputHandler(GameWorld myWorld) {
    // myBird now represents the gameWorld's bird.
   this.myWorld = myWorld;
   myBird = myWorld.getBird(); }

@Override
public boolean touchDown(int screenX, int screenY, int pointer, int button) {

    if (myWorld.isReady()) {
        myWorld.start();
    }

    myBird.onClick();

    if (myWorld.isGameOver() || myWorld.isHighScore()) {
        // Reset all variables, go to GameState.READ
        myWorld.restart();
    }

    return true;
}

@Override
public boolean keyDown(int keycode) {
    return false;
}

@Override
public boolean keyUp(int keycode) {
    return false;
}

@Override
public boolean keyTyped(char character) {
    return false;
}

@Override
public boolean touchUp(int screenX, int screenY, int pointer, int button) {
    return false;
}

@Override
public boolean touchDragged(int screenX, int screenY, int pointer) {
    return false;
}

@Override
public boolean mouseMoved(int screenX, int screenY) {
    return false;
}

@Override
public boolean scrolled(int amount) {
    return false;
}

}

Answer 1

创建一个方法，如果触摸位于矩形范围内，则返回 true。

public boolean ContainsPoint(Rectangle rectangle, Point touch)
{
    if (touch.X > rectangle.X && touch.X < rectangle.X + rectangle.Width &&
    touch.Y > rectangle.Y && touch.Y < rectangle.Y + rectangle.Height)
    return true;
    else
    return false;
}

您还可以向矩形类本身添加这样的方法，这样您就可以调用矩形，如下所示:矩形。

ContainsPoint(new Point(TouchXCoord, TouchYCoord));