wpf - 在 XAML 中关联 View 和 ViewModel 对，无需重复代码

Question

我已阅读 a very nice tutorial关于让 ViewModels 做他们的事情，而 View 只是通过数据绑定(bind)与 DataTemplates 自行切换。

我成功创建了一个具有 ApplicationViewModel 的窗口，而该窗口又具有硬编码的 DummyViewModel 作为其 CurrentScreen 属性

<Window x:Class="MyProject.Aplication"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:vm="clr-namespace:MyProject.ViewModels"
        xmlns:v="clr-namespace:MyProject.Views"
        xmlns:System="clr-namespace:System;assembly=mscorlib"
        Title="Killer Application" Height="900" Width="1440"
        WindowState="Maximized">

    <!-- This view has its viewmodel as data context, which has a CurrentScreen property -->
    <Window.DataContext>
        <vm:AplicationViewModel/>
    </Window.DataContext>

    <Window.Resources>
        <!-- each ViewModel will explicitly map to its current View - while this should happen EXPLICITLY, no? -->
        <DataTemplate DataType="{x:Type vm:DummyViewModel}">
            <v:DummyView/>
        </DataTemplate>
        <!-- Doc, are you telling me I'll have to fill this up for EVERY VIEW/VIEWMODEL? -->
        <DataTemplate DataType="{x:Type vm:YetAnotherViewModel}">
            <v:YetAnotherView/>
        </DataTemplate>
    </Window.Resources>

    <!-- the content is bound to CurrentScreen property of the data context -->
    <ContentControl Content="{Binding CurrentScreen}" />
</Window>

我想有一些(非常简单和直接，如果可能的话)方法来获得相同的结果，而不必为窗口可以显示的每个可能的屏幕详尽地编写一个 DataTemplate 窗口资源。有办法吗？

Answer 1

If you're doing MVVM, then you should be using an MVVM framework .例如，Caliburn.Micro将根据约定进行 View 定位和自动绑定(bind)。