java - HttpResponse 客户端协议(protocol)异常

Question

我有一个 HttpGet，一直工作得很好。最近，我获取信息的网页发生了变化。我基本上是从喊播服务器的歌曲元数据页面读取文本。此新 URL 将不允许 HttpResponse response = client.execute(method) 在此新 URL 上运行。它立即抛出客户端协议(protocol)异常，没有进一步的信息，所以我不知道出了什么问题。我下载了wireshark。这是响应:HTTP/1.0 200 OK。旧的 url 响应是 HTTP/1.1 200 OK。我已经在谷歌上搜索了几个小时，但没有找到任何帮助。

有人对此有建议或有任何帮助吗？

这是代码:

package com.joebutt.mouseworldradio;

import java.io.*;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.HttpStatus;
import org.apache.http.client.*;
import org.apache.http.client.methods.*;
import org.apache.http.impl.client.DefaultHttpClient;


import android.os.AsyncTask;
import android.util.Log;


public class HttpMetaData extends AsyncTask<Void, Void, String>
{

@Override
protected String doInBackground(Void... params)
{
    Log.d("MWR MetaData", "doInBackground called");
    HttpClient client = new DefaultHttpClient();
    HttpGet method = new HttpGet("http://wdwtoday.serverroom.us:4152/7.html");
    //HttpGet method = new HttpGet("http://38.96.148.18:4152/7.html");
    //method.setHeader("HTTP/1.1", "200 OK");
    //method.setHeader("Content-Type:", "text/html");
    //old url that worked just fine for 2 years
    //HttpGet method = new HttpGet("http://yp.shoutcast.com/Metadata_Info1.php?surl=" + Play.selectedUrl);
    String responseData = "";
    if(isCancelled())
    {
        return responseData;
    }
    try
    {
        //fails at the response!!
        HttpResponse response = client.execute(method);
        int status = response.getStatusLine().getStatusCode();
        String statusString = Integer.toString(status);
        Log.d("MWR Http status code", statusString);
        if (status == HttpStatus.SC_OK)
        {
            HttpEntity entity = response.getEntity();
            byte buffer[] = new byte[1024];
            InputStream inStream = entity.getContent();
            int numBytes = inStream.read(buffer);
            inStream.close();
            responseData = new String(buffer,0,numBytes);

            //get rid of the first part of the string
            if(responseData.length() > 13)
            {
                responseData = responseData.substring(13);

                //now get rid of the end of the string to clean it up
                //int length = responseData.length();
                int endPoint = responseData.indexOf("'");
                responseData = responseData.substring(0, endPoint);

                //old stuff wasnt used 8/2014
                //if (Play.selectedUrl.equals("http://38.96.148.91:4152"))
                //{
                    //int trimAmount = length - 37;
                    //responseData = responseData.substring(0, trimAmount);
                //}
                //else if (Play.selectedUrl.equals("http://38.96.148.91:4154"))
                //{
                //  int trimAmount = length - 31;
                    //responseData = responseData.substring(0, trimAmount);
                //}
            }
            else
            {
                responseData = "Data is not currently available";
            }
        }
        else
        {
            responseData = "Data is not currently available";
        }
    }
    catch(ClientProtocolException e)
    {
        Log.d("MWR MetaData", "Response Failure: " + e + "/" + responseData);
        responseData = "Data Error";
    }
    catch(IOException e)
    {
        Log.d("MWR MetaData", "IOException" + e + "/" + responseData);
        responseData = "Data is not currently available";
    }

    return responseData;
}

@Override
protected void onPostExecute(String result)
{

    Play.metaData=result;
    Log.d("MWR getMetaData", "onPostExecute Called");
}

}

Answer 1

好的，在 WinAmp 论坛的帮助下，我发现这个 url 需要通过用户代理“Mozilla”请求。

所以我添加了:

method.setHeader("User-Agent","Mozilla");

现在我收到了 200 OK 响应。

也许这会帮助其他人解决此类问题。

乔