java - 找到最小和第二小的数字

Question

这个程序应该找到x个数字中最小的和第二小的数字。程序每次都会找到最小的数字，但我在从键盘上替换第二小的数字时遇到问题。

 System.out.println("How many numbers?");
 int total = keyboard.nextInt();

 System.out.println("What is the first number");
 int small = keyboard.nextInt();

 System.out.println("whats the second number");
 int nest = keyboard.nextInt();
 // Assigning the first two numbers to smallest and second largest

 for (int i =2;i<total;i++) {                     
    System.out.println("whats the next number?");
    int number = keyboard.nextInt();

    if (number < small) {
       small = number;
    } // this part works (I think)

    if ((number > small) && (number < nest)) {
       nest = number;
    }//this part dont (I think)

 }//end forloop
 System.out.printf("The smallest numbers are %d and %d",small,nest); 

Answer 1

你只需要把顺序弄对就可以了。首先看这个数字是否小于最小的数字，如果是，则替换它，并将旧的最小数字移动到第二小的数字。否则，如果它小于第二小的数字，则替换它。

这是应该在循环中的代码:

if (number < small) {
    nest = small;
    small = number;
} else if (number < nest) {
    nest = number;
}