java - 猜谜游戏又玩麻烦了

Question

好吧，我尝试了一种方法，但每次我出于某种原因输入数字时，它都会显示“您想再玩一次吗”。这是我到目前为止所拥有的。我还能做什么，以便只有在用户猜出正确答案后，它才会询问他/她是否想再次玩？

import java.util.Random;
import java.util.Scanner;

public class GuessNumber {

    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);

        Random rand = new Random();
        int number = rand.nextInt(100) + 1;
        int guess;

        System.out.println("Guess the number between 1 and 100\n");

        guess = scan.nextInt();

        while (true) {
            if(guess < number)       
               System.out.println("Higher!");
            else if(guess > number)
               System.out.println("Lower!");
            else if (guess == number){
               System.out.println("Correct!");
            }
               guess = scan.nextInt();
       }
    }
  }

Answer 1

试试这个

class GuessNumber {

    static Random rand = new Random();
    static Scanner scan = new Scanner(System.in);
    static int number;

    public static void main(String[] args) {
        playGame();
    }

    public static void playGame() {
        number = rand.nextInt(100) + 1;
        System.out.println("Guess the number between 1 and 100");
        while (true) {
            int guess = scan.nextInt();
            if (guess < number) {
                System.out.println("Higher!");
            } else if (guess > number) {
                System.out.println("Lower!");
            } else if (guess == number) {
                System.out.println("Correct!");
                System.out.println("Do you like to play again?[1 for Yes/0 for No]");
                int val = scan2.next();
                if (val == 1)
                    playGame();
                else
                    break;
            }
        }
    }
}

或者不使用相同的扫描仪，您可以使用另一个扫描仪并获取字符串输入，如下所示

 else if (guess == number) {
      System.out.println("Correct!");
      Scanner scan2 = new Scanner(System.in);
      System.out.println("Do you like to play again?[Y/N]");
      String val = scan2.next();
      if (val.equalsIgnoreCase("Y"))
           playGame();
      else 
           break;
 }