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python - 如何使用 mpi4py 收集长度不等的数组

转载 作者:行者123 更新时间:2023-12-01 12:27:20 25 4
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期望的行为:

我正在尝试在不同节点上获取许多不同长度的列表,将它们收集到一个节点中,然后让该主节点将它们放在一组中。此列表名为 rout_array在每个节点。注意 rout_array 中的元素只是整数,并且在节点之间不唯一。

错误:

Traceback (most recent call last):
File "prout.py", line 160, in <module>
main()
File "prout.py", line 153, in main
num = DetermineRoutingNumber(steps, goal, vertexSetSize)
File "prout.py", line 129, in DetermineRoutingNumber
comm.Gather(send_buffer, recv_buffer, root = 0)

File "MPI\Comm.pyx", line 589, in mpi4py.MPI.Comm.Gather (c:\projects\mpi4py\src\mpi4py.MPI.c:97806)
File "MPI\msgbuffer.pxi", line 525, in mpi4py.MPI._p_msg_cco.for_gather (c:\projects\mpi4py\src\mpi4py.MPI.c:34678)
File "MPI\msgbuffer.pxi", line 446, in mpi4py.MPI._p_msg_cco.for_cco_send (c:\projects\mpi4py\src\mpi4py.MPI.c:33938)
File "MPI\msgbuffer.pxi", line 148, in mpi4py.MPI.message_simple (c:\projects\mpi4py\src\mpi4py.MPI.c:30349)
File "MPI\msgbuffer.pxi", line 93, in mpi4py.MPI.message_basic (c:\projects\mpi4py\src\mpi4py.MPI.c:29448)

KeyError: 'O'

我不知道如何得到 'O' 的 KeyError当我的代码中没有字符串时。所有列表都包含整数,numpy 数组包含整数,这里唯一事件的字典只有整数作为键。需要注意的是,每个节点都会输出这个错误。

代码:

import numpy, math
from mpi4py import MPI
from sympy.combinatorics import Permutation as Perm

def GetEdges(size,file):
"""This function takes in a file of edges in a graph in the form 'u,v'
without quotes, where u and v are vertices of the graph. It then
generates a permutation that swaps those vertices, and returns these
transpositions."""

edgeFile = open(file, "r")
edges = []
for line in edgeFile:
line = line.strip()
line = line.split(",")
for vertex in line:
line[line.index(vertex)] = int(vertex)
edges.append(Perm([line], size = size))

edgeFile.close()
edges.append(Perm([[size - 1]], size = size))

return edges


def AreDisjoint(p1,p2):
"""This function determines whether or not two permutations move any
common elements, and returns the appropriate boolean."""
v1 = set(p1.support())
v2 = set(p2.support())

return len(v1 & v2) == 0


def GetMatchings(edges, maxMatching, size):
"""This function takes in a set of edges given by GetEdges(), and
generates all possible matchings in the given graph. It then converts
each matching into its rank given by lexicographical order, and appends
that rank to a set, which is then returned."""

stepDict = {1:set(edges)}
steps = set(edges)
for i in range(1,maxMatching):
temp = set()
for p1 in stepDict[1]:
for p2 in stepDict[i]:
newPerm = p1 * p2
if AreDisjoint(p1,p2) and newPerm not in steps:
temp.add(newPerm)
steps.add(newPerm)

stepDict[i+1] = temp

newSteps = set()
for step in steps:
newSteps.add(step.rank())
return newSteps


def FromRank(rank,level):
"""This function takes in a rank and size of a permutation, then returns
the permutation that lies at the rank according to lexicographical
ordering. """

lst = list(range(level + 1))
perm = []
while lst:
fact = math.factorial(len(lst) - 1)
index, rank = divmod(rank, fact)
perm.append(lst.pop(index))
assert rank == 0
return perm


def SplitArrayBetweenNodes(rank, rem, length):
"""This function takes in the rank of a node and any remainder after
dividing up an array between all the nodes. It then returns a starting
and ending partition index unique to each node."""
if rem != 0:
if rank in list(range(rem)):
if rank == 0:
part_start = 0
part_end = length
else:
part_start = rank * (length + 1)
part_end = part_start + length
else:
part_start = rank * length + rem
part_end = part_start + length - 1
else:
part_start = rank * length
part_end = part_start + length - 1

return part_start, part_end


def DetermineRoutingNumber(steps, goal, vertexSetSize):
"""This function takes in the matchings created by GetMatchings(),
and calculates all possible products between its own elements. It then
takes all unique products, and calculates all possible prducts between
the matching set and the previous output. This repeats until all
permutations of a given type are found. The level at which this occurs
is then returned."""

comm = MPI.COMM_WORLD
rank = comm.Get_rank()
size = comm.Get_size()

length = len(steps)
rem = length % size
part_len = length // size

part_start, part_end = SplitArrayBetweenNodes(rank,rem, part_len)

permDict = {1: steps}
i = 1
while True:
rout_array = set()
work_array = set(list(permDict[i])[part_start:part_end + 1])

#Calculate all possible products
for p1 in permDict[1]:
for p2 in work_array:
p2_perm = Perm(FromRank(p2,vertexSetSize - 1))
p1_perm = Perm(FromRank(p1,vertexSetSize - 1))
new = p2_perm * p1_perm

if new(0) == 0 or new(0) == 1:
order = new.rank()
rout_array.add(order)

#All nodes send their work to master node
comm.Barrier()

send_buffer = numpy.array(rout_array)
sendcounts = numpy.array(comm.gather(len(rout_array), root = 0))

if rank == 0:
recv_buffer = numpy.empty(sum(sendcounts), dtype = int)
else:
recv_buffer = None

comm.Gatherv(sendbuf = send_buffer, recvbuf = (recv_buffer, sendcounts), root = 0)

#Generate input for next level of the loop, and weed out repeats.
permDict[i+1] = rout_array
for j in range(1,i+1):
permDict[i+1] = permDict[i+1] - permDict[j]


def main():
file = "EdgesQ2.txt"
maxMatching = 2
vertexSetSize = 4

edges = GetEdges(vertexSetSize, file)
steps = GetMatchings(edges, maxMatching, vertexSetSize)
goal = 2 * math.factorial(vertexSetSize-1)

num = DetermineRoutingNumber(steps, goal, vertexSetSize)
print(num)


main()

测试用例:

EdgesQ2.txt:

请注意 maxMatching = 2vertexSetSize = 4在这个例子中。输出应为 3 .

0,1
1,2
2,3
0,3

EdgesQ3.txt:

请注意 maxMatching = 4vertexSetSize = 8在这个例子中。输出应为 4 .

0,1
0,3
0,4
1,2
1,5
2,3
2,6
3,7
4,5
4,7
5,6
6,7

最佳答案

如果不同进程的长度不同,则需要使用向量变体 Gatherv .使用该函数,您可以提供一个包含各种长度(recvcounts)的数组。

不幸的是,mpi4py 文档目前没有描述如何使用 Gatherv或任何其他载体变体。这是一个简单的例子:

#!/usr/bin/env python3

import numpy as np
from mpi4py import MPI
import random

comm = MPI.COMM_WORLD
rank = comm.Get_rank()
root = 0

local_array = [rank] * random.randint(2, 5)
print("rank: {}, local_array: {}".format(rank, local_array))

sendbuf = np.array(local_array)

# Collect local array sizes using the high-level mpi4py gather
sendcounts = np.array(comm.gather(len(sendbuf), root))

if rank == root:
print("sendcounts: {}, total: {}".format(sendcounts, sum(sendcounts)))
recvbuf = np.empty(sum(sendcounts), dtype=int)
else:
recvbuf = None

comm.Gatherv(sendbuf=sendbuf, recvbuf=(recvbuf, sendcounts), root=root)
if rank == root:
print("Gathered array: {}".format(recvbuf))

如您所见,mpi4py 不将 sendcounts 或 recvcounts 作为额外参数,而是作为 recvbuf 的元组/列表。范围。如果您通过 (recvbuf, sendcounts)它将从 recvbuf 派生类型。将进行位移/偏移,以使来自所有等级的数据连续存储并按等级排序。

基本上,mpi4py 会疯狂地猜测您对 recvbuf 的各种形式可能意味着什么。范围。完整且明确的形式是 (buffer, counts, displacements, type) .

关于 KeyError 的编辑:

相当困惑的名称 rout_arrayset ,这不是 numpy.array 的有效输入.一个 set既不是序列也没有数组接口(interface)。不幸的是, numpy.array 并没有失败,而是创建一个非常奇怪的 ndarray没有尺寸的物体。您可以将数组创建包装在列表中:
send_buffer = numpy.array(list(rout_array))

集体工作,但循环不会终止,考虑到没有 return,这并不奇怪。或 breakwhile true循环进入 DetermineRoutingNumber .

关于python - 如何使用 mpi4py 收集长度不等的数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37999866/

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