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python-3.x - 如何为贪吃蛇游戏生成食物

转载 作者:行者123 更新时间:2023-12-01 12:27:18 25 4
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我不知道如何生成蛇吃的食物。我知道蛇在第 97 行和第 98 行的位置,我创建了一个类来生成一个像素,我想在第 22 行绘制一个和平的食物(编辑:可能应该是一个函数,评论#def(?)在编码)。我所要做的就是从随机分配的位置在 x 和 y 坐标处添加 15 个像素,然后打印它以获得一个 block 。

问题是检查我吃不吃。它应该是这样的:

if x >= x_food && x <= x_food + 15 || y >= y_food && y <= y_food + 15:
...add a point and make snake longer...

问题是出于某种原因将它们放在一起。有人可以给我提示或解决我应该如何编写此类,以便我可以继续处理其他问题吗?谢谢!

import pygame
import random

#Global variables
#Color
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)

#Start length of snake
snake_length = 3

#Set the width of the segments of the snake
segment_width = 15
segment_height = 15
# Margin within each segment
segment_margin = 3

#Set initial speed
x_change = segment_width + segment_margin
y_change = 0

#def (?)
class Food():
#Class to print food
x_food = random.randint(0, 785)
y_food = random.randint(0, 585)


class Segment(pygame.sprite.Sprite):
""" Class to represent the segment of the snake. """
# Methods
# Constructer function
def __init__(self, x, y):
#Call the parents constructor
super().__init__()

#Set height, width
self.image = pygame.Surface([segment_width, segment_height])
self.image.fill(WHITE)

#Make our top-left corner the passed-in location.
self.rect = self.image.get_rect()
self.rect.x = x
self.rect.y = y

#Call this function so the Pygame library can initialize itself
pygame.init()

#Create an 800x600 size screen
screen = pygame.display.set_mode([800, 600])

#Set the title of the window
pygame.display.set_caption("Snake")

allspriteslist = pygame.sprite.Group()

#Create an initial snake
snake_segments = []
for i in range(snake_length):
x = 250 - (segment_width + segment_margin) * i
y = 30
segment = Segment(x, y)
snake_segments.append(segment)
allspriteslist.add(segment)

clock = pygame.time.Clock()
done = False

while not done:

for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True

#Set the speed based on the key pressed
#We want the speed to be enough that we move a full
#Segment, plus the margin
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x_change = (segment_width + segment_margin) * -1
y_change = 0
if event.key == pygame.K_RIGHT:
x_change = (segment_width + segment_margin)
y_change = 0
if event.key == pygame.K_UP:
x_change = 0
y_change = (segment_height + segment_margin) * -1
if event.key == pygame.K_DOWN:
x_change = 0
y_change = (segment_width + segment_margin)

#Get rid of last segment of the snake
#.pop() command removes last item in list
old_segment = snake_segments.pop()
allspriteslist.remove(old_segment)

#Figure out where new segment will be
x = snake_segments[0].rect.x + x_change
y = snake_segments[0].rect.y + y_change
segment = Segment(x, y)

#Insert new segment to the list
snake_segments.insert(0, segment)
allspriteslist.add(segment)

#Draw
#Clear screen
screen.fill(BLACK)

allspriteslist.draw(screen)

#Flip screen
pygame.display.flip()

#Pause
clock.tick(5)

pygame.quit()

最佳答案

我拿了你的代码,我想我解决了一些问题,请注意,这只会在蛇越过街区时进行监控,然后它会打印:yummy,所以你必须添加细节,还要注意我不使用你的类来生成食物:

import pygame
import random

#Global variables
#Color
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)

#Start length of snake
snake_length = 3

#Set the width of the segments of the snake
segment_width = 15
segment_height = 15
# Margin within each segment
segment_margin = 3

#Set initial speed
x_change = segment_width + segment_margin
y_change = 0

#def (?)
class Food():
#Class to print food
x_food = random.randint(0, 785)
y_food = random.randint(0, 585)


class Segment(pygame.sprite.Sprite):
""" Class to represent the segment of the snake. """
# Methods
# Constructer function
def __init__(self, x, y):
#Call the parents constructor
super().__init__()

#Set height, width
self.image = pygame.Surface([segment_width, segment_height])
self.image.fill(WHITE)

#Make our top-left corner the passed-in location.
self.rect = self.image.get_rect()
self.rect.x = x
self.rect.y = y

#Call this function so the Pygame library can initialize itself
pygame.init()

#Create an 800x600 size screen
screen = pygame.display.set_mode([800, 600])

#Set the title of the window
pygame.display.set_caption("Snake")

allspriteslist = pygame.sprite.Group()

#Create an initial snake
snake_segments = []
for i in range(snake_length):
x = 250 - (segment_width + segment_margin) * i
y = 30
segment = Segment(x, y)
snake_segments.append(segment)
allspriteslist.add(segment)

clock = pygame.time.Clock()
done = False
x_food = random.randint(0, 785)
y_food = random.randint(0, 585)

while not done:

for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True

#Set the speed based on the key pressed
#We want the speed to be enough that we move a full
#Segment, plus the margin
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x_change = (segment_width + segment_margin) * -1
y_change = 0
if event.key == pygame.K_RIGHT:
x_change = (segment_width + segment_margin)
y_change = 0
if event.key == pygame.K_UP:
x_change = 0
y_change = (segment_height + segment_margin) * -1
if event.key == pygame.K_DOWN:
x_change = 0
y_change = (segment_width + segment_margin)

if y < y_food+30:
if x > x_food and x < x_food+30 or x+20 > x_food and x+20<x_food+30:
print('yummy')



#Get rid of last segment of the snake
#.pop() command removes last item in list
old_segment = snake_segments.pop()
allspriteslist.remove(old_segment)

#Figure out where new segment will be
x = snake_segments[0].rect.x + x_change
y = snake_segments[0].rect.y + y_change
segment = Segment(x, y)

#Insert new segment to the list
snake_segments.insert(0, segment)
allspriteslist.add(segment)

#Draw
#Clear screen
screen.fill(BLACK)
pygame.draw.rect(screen, WHITE, [x_food, y_food, 30, 30])

allspriteslist.draw(screen)

#Flip screen
pygame.display.flip()

#Pause
clock.tick(5)

pygame.quit()

希望对您有所帮助,谢谢!

关于python-3.x - 如何为贪吃蛇游戏生成食物,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38041747/

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