java - 方法不打印java中的所有值

Question

我有2个java程序，第一个程序从用户那里获取有关员工的所有信息(id，姓名，部门等)并打印出来，第二个程序让用户选择有多少员工，然后需要像(员工ID，姓名等)这样的值，这个程序使用一个数组来存储值，它应该打印不同员工的所有值，但是当我运行程序时，第二组值覆盖第一组值并打印第二组值两次，我是初学者，所以请帮助

这是第一个程序

import java.util.Scanner;

public class payroll2
{
    public static void main(String args[])
    {
        payroll2 payroll = new payroll2();
        payroll.SetPayrollDetail();
        payroll.SetBonus();
        payroll.SetCommission();
        payroll.SetNssf();
        payroll.SetNetSalary();
        payroll.GetPayroll();
    }

    Scanner myScanner=new Scanner(System.in);
    int empID;
    String empName;
    String empDept;
    String designation;
    int basicSalary;

    double bonus;
    double commission;
    double nssf;
    double netSalary;


    public void SetPayrollDetail()
    {
        System.out.println("Enter ID: ");
        empID = myScanner.nextInt();

        System.out.println("Enter Name: ");
        empName = myScanner.next();

        System.out.println("Enter Department (Marketing or Other): ");
        empDept = myScanner.next();

        System.out.println("Enter Designation (Manager, Executive or Other): ");
        designation = myScanner.next();

        System.out.println("Enter Basic Salary: ");
        basicSalary = myScanner.nextInt();

    }

    public void SetBonus()
    {
        if(basicSalary < 1500){
            bonus = 0.0;
        }
        else if(basicSalary>=1500 && basicSalary<3000){
            bonus = basicSalary * (12.0/100.0);
        }
        else if(basicSalary>=3000 && basicSalary<5000){
            bonus = basicSalary * (15.0/100.0);
        }
        else{
            bonus = basicSalary * (25.0/100.0);
        }
    }

    public void SetCommission()
    {
        if( empDept.equalsIgnoreCase("other") ){
            commission = 0.0;
        }
        else if( empDept.equalsIgnoreCase("marketing") && designation.equalsIgnoreCase("manager") ){
            commission = basicSalary * (30.0/100.0);
        }
        else if( empDept.equalsIgnoreCase("marketing") && designation.equalsIgnoreCase("executive") ){
                    commission = basicSalary * (15.0/100.0);
        }
        else if( empDept.equalsIgnoreCase("marketing") && designation.equalsIgnoreCase("other") ){
                    commission = basicSalary * (10.0/100.0);
        }
        else{
            commission = 0.0;
        }

    }

    public void SetNssf()
    {
        if(basicSalary < 1500){
            nssf = basicSalary * (5.0/100.0);
        }
        else if(basicSalary>=1500 && basicSalary<3000){
            nssf = basicSalary * (8.0/100.0);
        }
        else if(basicSalary>=3000 && basicSalary<5000){
            nssf = basicSalary * (12.0/100.0);
        }
        else if(basicSalary>=5000 && basicSalary<7000){
            nssf = basicSalary * (15.0/100.0);
        }
        else if(basicSalary>=7000 && basicSalary<10000){
            nssf = basicSalary * (20.0/100.0);
        }
        else{
            nssf = basicSalary * (25.0/100.0);
        }

    }

    public void SetNetSalary()
    {
        netSalary = ( basicSalary + commission + bonus ) - nssf;

    }

    public void GetPayroll()
    {
        System.out.println("\n\nPayroll Details \n _____________________");
        System.out.println("ID:\t\t" + empID);
        System.out.println("name:\t\t" + empName);

        System.out.println("Bonus:\t\t" + bonus);
        System.out.println("Commission:\t"+commission);
        System.out.println("NSSF:\t\t"+nssf);
        System.out.println("Net Salary:\t"+netSalary);

    }
}

这是第二个程序

 import java.util.Scanner;

  public class display{

public static void main(String[]args){

    Scanner scan = new Scanner(System.in);

    int counter;
    int limit;

    System.out.println("How many employess do u want to enter?\n Enter here: ");
    limit = scan.nextInt();

    int[] a = new int[limit];
    payroll2 payroll = new payroll2();

    for(counter=1; counter<=limit; counter++){
        System.out.println("\n\nEnter employee "+counter+" details\n");
        payroll.SetPayrollDetail();
        payroll.SetBonus();
        payroll.SetCommission();
        payroll.SetNssf();
        payroll.SetNetSalary();

    }

    for(counter=1; counter<=limit; counter++){
        payroll.GetPayroll();
        //System.out.println(a);
    }

}

}

Answer 1

这是有问题的代码区域:

for(counter=1; counter<=limit; counter++){
    System.out.println("\n\nEnter employee "+counter+" details\n");
    payroll.SetPayrollDetail();
    payroll.SetBonus();
    payroll.SetCommission();
    payroll.SetNssf();
    payroll.SetNetSalary();

}

for(counter=1; counter<=limit; counter++){
    payroll.GetPayroll();
    //System.out.println(a);
}

如果你想一下这是做什么的。因此 payroll2 对象是一个单一实体。当您在第一个 for 循环中输入它们时，您就创建了一个人。然后，如果您第二次或第三次循环，就会覆盖该人，因为您正在保存到同一个变量。

然后，当您循环第二个循环时，您将打印工资单实体，其中保存了最后输入的人员的值。由于其他数据被覆盖，因此同一个人打印限制时间也就不足为奇了。

您想要做的是构建一个工资单实体数组。此代码完成此操作:

payroll2[] PayrollList = new payroll2[limit];  // establish the array with correct size
for(counter=0; counter<=limit - 1; counter++){  // bounds of the array are 0 to limit - 1
    payroll = new payroll();  // hard reset of the variable to make sure data is cleared
    System.out.println("\n\nEnter employee "+counter+" details\n");
    payroll.SetPayrollDetail();
    payroll.SetBonus();
    payroll.SetCommission();
    payroll.SetNssf();
    payroll.SetNetSalary();

    PayrollList[counter] = payroll; // adds it to the array at position counter
}

for(counter=0; counter<=limit - 1; counter++){
    PayrollList[counter].GetPayroll(); // gets the payroll2 object from the array and calls its function
}

免责声明:我没有通过编译器运行修改后的代码，因此它可能不是 100% 语法正确，但非常接近。