java - 函数仅返回偶数

Question

我的程序应该打印给定数字的所有百分比。它工作正常，直到我添加一个为结果着色的函数(红色低，绿色高)。现在它只打印奇数或偶数，但不能同时打印两者。至于颜色，它是反向工作的，从绿色到红色。我希望打印所有结果并根据其值着色。

这是代码

public class Window extends JFrame implements ActionListener{

private JButton theButton = new JButton("Calculer sur 100");
private JEditorPane text = new JEditorPane();
private JTextField textField = new JTextField("Écrire un nombre");
private JScrollPane scroller = new JScrollPane(text);
private StringBuilder sb = new StringBuilder();
private Style style;

public Window() {
    setLayout(new BorderLayout());
    setTitle("Test");
    setSize(400, 500);
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    setLocationRelativeTo(null);
    text.setContentType("text/html");

    theButton.addActionListener(this);

    getContentPane().add(scroller, BorderLayout.CENTER);
    getContentPane().add(textField, BorderLayout.NORTH);
    getContentPane().add(theButton, BorderLayout.SOUTH);
    setVisible(true);
}

/**
 * Prints the result on text
 * @param num
 */
private void print100(int num) {
    for (int i = 1; i < num + 1; i++) {
        text.setText(appendString(i));
    }
}


/**
 * Color from red to green according to the result
 * @param a
 * @return a haxaecimal to color the answer
 */
private String colorOnDigit(double a) {
    double green, red;
    int g, r;
    double power = a;
    int blue = 0;

    green = 255 * Math.sqrt( Math.cos ( power * Math.PI / 200 ));
    red = 255 * Math.sqrt( Math.sin ( power * Math.PI / 200 ));

    int precision = 10; //Number of zero = number of digits
    green = Math.floor(green * precision + .5) / precision;
    red = Math.floor(red * precision + .5) / precision;

    r = (int) red;
    g = (int) green;

    String hex = String.format("#%02x%02x%02x", r, g, blue);

    System.out.println("blue " + blue);
    System.out.println("Green " + green);
    System.out.println("Red " + red);
    System.out.println("----------");
    return "<font color = \"" + hex + ">";
}

/**
 * convert the number to string 
 * @param i
 * @return a string that contains the information
 */
private String appendString(int i){
    double a = doMath(i, checkForNumber());

    String s = "<br>" + colorOnDigit(a) + i + " : " + a + "</font>";

    return sb.append(s).toString();
}

/**
* Check if the text in the text is numbers
* return numl
*/
private int checkForNumber() {
    int numl;
    try {
        numl = Integer.parseInt(textField.getText());
    } catch (NumberFormatException e) {
        text.setText("Essayer avec des nombres...");
        return 0;
    }
    return numl;
}

/**
* leave specific number of digit after the dot
* return myNum
*/
private double doMath(int i, int num) {
    double myNum = ((double) i / num) * 100;
    int precision = 100; //Number of zero = number of digits
    myNum = Math.floor(myNum * precision + .5) / precision;
    return myNum;
}

public void actionPerformed(ActionEvent e) {
    if (e.getSource() == theButton) {
        text.setText("");
        print100(checkForNumber());
    }
}

}

当我调用System.out.print()时，它具有我在JTextField中输入的确切数字。

我在谷歌和 StackOverflow 上都没有找到任何答案。我无法弄清楚，但我很确定答案很简单。有什么想法吗？

<小时/>

我已经弄清楚了颜色。我需要做的就是乘法然后除法而不是除法。(即)

//Before
green = 255 * Math.sqrt( Math.cos ( power * Math.PI / 200 ));
red = 255 * Math.sqrt( Math.sin ( power * Math.PI / 200 ));

//After
green = 255 * Math.sqrt( Math.cos ( power / Math.PI * 200 ));
red = 255 * Math.sqrt( Math.sin ( power / Math.PI * 200 ));

Answer 1

为了测试，我将您的应用程序稍微更改为一个简单的 Java 应用程序。我通过模拟 textField 的输入来测试这个程序。 (修改为由 print100 方法的参数给出)。

但是，程序给出从 1 到 100 的正常输出，不跳过奇数，偶数 12 作为 print100 的参数给出。方法。

无论如何，你应该将 colorOnDigit 的最后一行更改为 return "<font color = \"" + hex + "\">"; 。缺少右双引号(应包含在生成的 HTML 标记中)。 我认为这可能是输出中缺少奇怪标记的原因。

public class OneHundred {

    /**
    * leave specific number of digit after the dot
    * return myNum
    */
    private static double doMath(int i, int num) {
        double myNum = ((double) i / num) * 100;
        int precision = 100; //Number of zero = number of digits
        myNum = Math.floor(myNum * precision + .5) / precision;
        return myNum;
    }

    /**
     * Color from red to green according to the result
     * @param a
     * @return a haxaecimal to color the answer
     */
    private static String colorOnDigit(double a) {
        double green, red;
        int g, r;
        double power = a;
        int blue = 0;

        green = 255 * Math.sqrt( Math.cos ( power * Math.PI / 200 ));
        red = 255 * Math.sqrt( Math.sin ( power * Math.PI / 200 ));

        int precision = 10; //Number of zero = number of digits
        green = Math.floor(green * precision + .5) / precision;
        red = Math.floor(red * precision + .5) / precision;

        r = (int) red;
        g = (int) green;

        String hex = String.format("#%02x%02x%02x", r, g, blue);

        System.out.println("blue " + blue);
        System.out.println("Green " + green);
        System.out.println("Red " + red);
        System.out.println("----------");
        return "<font color = \"" + hex + "\">";
    }

    /**
     * convert the number to string 
     * @param i
     * @return a string that contains the information
     */
    private static String appendString(StringBuilder b, int i, int input){
        double a = doMath(i, input /* assumed an arbitrary input*/ );

        String s = "<br>" + colorOnDigit(a) + i + " : " + a + "</font>\n";

        return b.append(s).toString();
    }

    private static String print100(int num) {
        StringBuilder text = new StringBuilder();

        for (int i = 1; i < 100 + 1; i++) {
            appendString(text, i, num);
        }

        return text.toString();
    }

    /**
     * @param args
     */
    public static void main(String[] args) {
        String l = print100(7);
        System.err.println(l);
    }

}