java - 如何将随机 int 转换为 String 以在 if/else 中使用？

Question

所以我正在为我的 AP Comp Sci 类(class)编写一个程序，我需要一些解析整数等方面的帮助。

如何获取一个随机整数并将其转换为可在 if/else 语句中使用的字符串？

import java.awt.*;
import java.awt.event.*;
import java.awt.Container;
import javax.swing.*;
import java.lang.*;
import java.io.*;
import java.util.*;

class LibraryGUI {

// variables and objects
JFrame frame, frame2, frame3;
JPanel panel, panel2, panel3;
JLabel label, label2, label3, label4;
JButton button1;
JButton button2, button3, enter2;
JTextField username, logincred;

Random r = new Random();

public LibraryGUI()
{
    frame = new JFrame("LexCorp Library");
    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    label = new JLabel("Welcome to LexCorp Library");

    button1 = new JButton("Login");
    button1.addActionListener(new ActionListener(){
        public void actionPerformed(ActionEvent e){
            frame3 = new JFrame("Find Account");
            panel3 = new JPanel();
            enter2 = new JButton("Enter");
            frame3.setLayout(new GridLayout(1,1));

            panel3.setBackground(Color.white);
            panel3.setSize(700,700);

            label4 = new JLabel("Enter account number");
            logincred = new JTextField("\t\t");

            logincred.addActionListener(new ActionListener(){
                public void actionPerformed(ActionEvent j){
                    String choose = logincred.getText();
                }
            });

            panel3.add(label4);
            panel3.add(logincred);
            panel3.add(enter2);

            frame3.getContentPane().add (panel3);

            frame3.pack();
            frame3.setVisible(true);

            //internalcode
        }
    });

    button2 = new JButton("Make a new Account");
    button2.addActionListener(new ActionListener(){
        public void actionPerformed(ActionEvent f){
            //GUI Section
            frame2 = new JFrame("Make a new account");
            //frame2.setLayout(new GridLayout(4,4));
            panel2 = new JPanel();

            panel2.setLayout(new GridLayout(4,3));
            //panel2.setLayout(new FlowLayout());

            label2 = new JLabel("Account's name");
            username = new JTextField();

            int acc = r.nextInt(1000);

            label3 = new JLabel("Your account number is " +acc);

            button3 = new JButton("Enter");
            button3.addActionListener(new ActionListener(){
                public void actionPerformed(ActionEvent ent){
                    JOptionPane.showMessageDialog(frame, "Account Created");
                    frame2.dispose();
                }
            });

            panel2.add(label2);

            panel2.add(username);
            panel2.add(button3);
            panel2.add(label3);

            frame2.pack();

            username.addActionListener(new ActionListener(){
                public void actionPerformed(ActionEvent ae){
                    String user = username.getText();
                    System.out.println(user);
                }
            });

            panel2.setSize(700,700);
            panel2.setBackground(Color.LIGHT_GRAY);

            frame2.getContentPane().add (panel2);
            frame2.pack();
            frame2.setVisible(true);

            //internalCode
        }
    });

    //panel properties
    panel = new JPanel();
    panel.setSize(700,700);
    panel.setLayout(new GridLayout(10,10));
    panel.setBackground(Color.yellow);

    //add-ins
    panel.add(label);
    panel.add(button1);
    panel.add(button2);

    frame.getContentPane().add (panel);
}

    public void display()
    {
        frame.pack();
        frame.setVisible(true);
    }
}

Answer 1

(take an..) integer and turn it into a string that can be used inside an IF ElSE

不如不转换它？ if 语句的条件可以使用整数，并且比字符串!

EG

int x = random.nextInt(100); 
if (x < 50) { 
    //..