java - 对整数数组进行排序

Question

我的程序遇到的问题是，当我打印所有数字时，我输入的第一个数字重复两次并替换了第二个数字

例如。如果我输入 1,3,5,7,9,11,13,15,17,19 输出为 1,1,5,7,9,11,13,15,17,19

我该如何解决这个问题？

import java.util.Scanner;
import java.util.Arrays;

public class InputSort_Integers
{
public static void main(String[] args)
{
    // Declarations
      final  int[] count = new int [10];

    // Scanner 
    Scanner scanner = new Scanner(System.in);

    // Scanner Loop
    for (int i = 0; i < count.length; i++)
    {

        System.out.print("Enter " + count.length + " numbers (Press enter after each entry): ");  
        count[i] = scanner.nextInt();       

    }

    // Print sorted number
    int sorted = printNumbers(count);                                                 

}

public static int printNumbers(int[] count)
{

    // Print loop
    for (int i=0; i<count.length; i++)
    {
        System.out.println(count[i]);
    // Sort Numbers
        Arrays.sort(count);

    }
 return count.length;
} 

}

Answer 1

您正在打印第一个数字，然后在循环内进行排序。您应该在循环开始之前对数字进行一次排序。将您的 printNumbers 方法更改为:

public static int printNumbers(int[] count)
{
    // Sort Numbers
    Arrays.sort(count);

    // Print loop
    for (int i=0; i<count.length; i++)
    {
        System.out.println(count[i]); 
    }
    return count.length;
}