java - PowerMock/EasyMock : Set expectation on final method that would throw exception

Question

如果我根本无法安全地调用该方法，如何设置对 final方法的期望？ PowerMock 应该确保调用被模拟，但我什至无法到达那个阶段:

WithFinal.java:

public class WithFinal {
    public final void finalMethod() {
        throw new RuntimeException();
    }
}

CallsFinal.java:

public class CallsFinal {
    private WithFinal withFinal;

    public CallsFinal(WithFinal withFinal) {
        this.withFinal = withFinal;
    }

    public void callFinal() {
        withFinal.finalMethod();
    }
}

PowerMockTest.java:

import org.easymock.EasyMock;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.powermock.modules.junit4.PowerMockRunner;
import org.powermock.core.classloader.annotations.PrepareForTest;

import static org.powermock.api.easymock.PowerMock.*;

@RunWith(PowerMockRunner.class)
@PrepareForTest(CallsFinal.class)
public class PowerMockTest {
    @Test public void testFinal() {
        WithFinal mock = createMock(WithFinal.class);
        CallsFinal callsFinal = new CallsFinal(mock);
        mock.finalMethod();
        EasyMock.expectLastCall().atLeastOnce();
        replay(mock);
        callsFinal.callFinal();
        verify(mock);
    }
}

我在第一次调用 mock.finalMethod() 时得到一个 RuntimeException，这是有道理的，但我认为 PowerMock 的全部意义在于使这成为可能？

Answer 1

测试类中存在一个简单的错误:它应该是 @PrepareForTest(WithFinal.class)，而不是 @PrepareForTest(CallsFinal.class)。

PowerMock 仅要求在从 JRE 模拟系统类时为测试准备好调用类；否则，需要准备的是要模拟的类本身。

最后，我要提到的是另一个可以在这里使用的模拟库，它是我开发的:JMockit。有了它，测试可以写成:

import org.junit.*;
import mockit.*;

public class JMockitTest {
    @Tested CallsFinal callsFinal;
    @Injectable WithFinal mock;

    @Test public void testFinal() {
        new Expectations() {{ mock.finalMethod(); }};

        callsFinal.callFinal();
    }
}