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java - 如何在java中读取受密码保护的.xls文件?

转载 作者:行者123 更新时间:2023-12-01 12:04:19 30 4
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我有一个代码可以在java中读取 protected Excel,但是该代码给了我错误。我的java代码。

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.security.GeneralSecurityException;
import java.util.Iterator;

import org.apache.poi.hssf.usermodel.HSSFCell;
import org.apache.poi.hssf.usermodel.HSSFRow;
import org.apache.poi.hssf.usermodel.HSSFSheet;
import org.apache.poi.hssf.usermodel.HSSFWorkbook;
import org.apache.poi.poifs.crypt.Decryptor;
import org.apache.poi.poifs.crypt.EncryptionInfo;
import org.apache.poi.poifs.filesystem.POIFSFileSystem;

public class REadProtectedExcel {
public static void main(String[] args) {
String fname = "D:/Vijay/BRS_docs/10168/20.11.2014/20.11.2014/JCR_30.12.14_I Pay.xls";
try {
POIFSFileSystem fs = new POIFSFileSystem(new FileInputStream(fname));
EncryptionInfo info = new EncryptionInfo(fs);
Decryptor d = Decryptor.getInstance(info);
if (d.verifyPassword("vijay")) {
System.out.println("Password correct");
FileInputStream fis = new FileInputStream(fname);
HSSFWorkbook workbook = new HSSFWorkbook(fis);
HSSFSheet sheet = workbook.getSheetAt(0);
Iterator rowIter = sheet.rowIterator();
while (rowIter.hasNext()) {
HSSFRow myRow = (HSSFRow) rowIter.next();
Iterator cellIter = myRow.cellIterator();
while (cellIter.hasNext()) {
String cellvalue = "";
HSSFCell myCell = (HSSFCell) cellIter.next();
if (myCell.getCellType() == HSSFCell.CELL_TYPE_STRING) {
cellvalue = myCell.getStringCellValue();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_NUMERIC) {
cellvalue = "" + myCell.getNumericCellValue();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_BOOLEAN) {
cellvalue = "" + myCell.getBooleanCellValue();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_FORMULA) {
cellvalue = "" + myCell.getCellFormula();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_BLANK) {
cellvalue = "";
}
System.out.println("cellvalue--" + cellvalue);
}
}
} else {
System.out.println("Password wrong");
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (GeneralSecurityException e) {
e.printStackTrace();
}
}
}

这段代码给了我以下错误。

java.io.FileNotFoundException: no such entry: "EncryptionInfo"
at org.apache.poi.poifs.filesystem.DirectoryNode.getEntry(DirectoryNode.java:375)
at org.apache.poi.poifs.filesystem.DirectoryNode.createDocumentInputStream(DirectoryNode.java:177)
at org.apache.poi.poifs.crypt.EncryptionInfo.<init>(EncryptionInfo.java:45)
at org.apache.poi.poifs.crypt.EncryptionInfo.<init>(EncryptionInfo.java:39)
at com.test.arrayList.REadProtectedExcel.main(REadProtectedExcel.java:22)
  • 我正在使用 poi3.9 jar、xmlbeans-2.3.0jar、poi-ooml-3.6
  • 我没有遇到这个问题。提前致谢。
  • 或者请分享另一种读取 .xls 文件的方法。

最佳答案

Apache POI provides documentation on Encryption on the website 。如果您转到Apache POI homepage并查看左侧菜单顶部附近,您会发现它链接在 Encryption Support 下。我强烈建议您阅读它!

随后您将看到,您编写的代码适用于加密的 .xlsx 文件,该文件使用与旧版 .xls 非常不同的方式来保护文件> 文件

正如文档所解释的,对于受密码保护的 .xls 文件,您需要做的就是:

String myPassword = "password";
org.apache.poi.hssf.record.crypto.Biff8EncryptionKey.setCurrentUserPassword(myPassword);
HSSFWorkbook wb = new HSSFWorkbook(stream);

关于java - 如何在java中读取受密码保护的.xls文件?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27741124/

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