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java - Gson json解析不起作用

转载 作者:行者123 更新时间:2023-12-01 12:03:46 25 4
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我正在解析 json 格式的文件,我通过

访问该文件

http://api.crossref.org/works?rows=1000&offset=6000000

大约有 7100 万条不同的发布记录,而我给出的链接仅显示 1000 条。在我的 java 代码中,gson 解析器大部分工作正常,但有时会出现如下错误:

com.google.gson.JsonSyntaxException: com.google.gson.stream.MalformedJsonException: Unterminated string at line 2 column 1
at com.google.gson.internal.Streams.parse(Streams.java:56)
at com.google.gson.JsonParser.parse(JsonParser.java:84)
at com.google.gson.JsonParser.parse(JsonParser.java:59)
at com.google.gson.JsonParser.parse(JsonParser.java:45)
at connectingurl.CrossRefFullTextToTable.<init>(CrossRefFullTextToTable.java:84)
at connectingurl.CrossRefFullTextToTable.main(CrossRefFullTextToTable.java:181)
Caused by: com.google.gson.stream.MalformedJsonException: Unterminated string at line 2 column 1
at com.google.gson.stream.JsonReader.syntaxError(JsonReader.java:1310)
at com.google.gson.stream.JsonReader.nextString(JsonReader.java:1046)
at com.google.gson.stream.JsonReader.nextValue(JsonReader.java:784)
at com.google.gson.stream.JsonReader.objectValue(JsonReader.java:766)
at com.google.gson.stream.JsonReader.peek(JsonReader.java:380)
at com.google.gson.internal.bind.TypeAdapters$25.read(TypeAdapters.java:635)
at com.google.gson.internal.bind.TypeAdapters$25.read(TypeAdapters.java:658)
at com.google.gson.internal.bind.TypeAdapters$25.read(TypeAdapters.java:650)
at com.google.gson.internal.bind.TypeAdapters$25.read(TypeAdapters.java:658)
at com.google.gson.internal.bind.TypeAdapters$25.read(TypeAdapters.java:658)
at com.google.gson.internal.bind.TypeAdapters$25.read(TypeAdapters.java:633)
at com.google.gson.internal.Streams.parse(Streams.java:44)

当我搜索它时,很可能存在内存问题。

这是我的java代码的一部分:

if(code == 200){

String full_text_link = "";
String license = "";

BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream(), "UTF-8"));
StringBuilder sb = new StringBuilder();

String inputLine;
while ((inputLine = in.readLine()) != null) {
sb.append(inputLine + System.getProperty("line.separator"));
}
in.close();
String jsonLine = sb.toString();


JsonElement jelement = new JsonParser().parse(jsonLine);
JsonObject jobject = jelement.getAsJsonObject();
jobject = jobject.getAsJsonObject("message");
JsonArray jarray_items = jobject.getAsJsonArray("items");

...
}

错误来自以下行:

JsonElement jelement = new JsonParser().parse(jsonLine);

看来gson可能有这样的问题。是否有任何其他建议使用另一个解析器或者我应该添加我的代码?

提前致谢...

最佳答案

while ((inputLine = in.readLine()) != null) {
sb.append(inputLine + System.getProperty("line.separator"));
}

你基本上是在无缘无故地修改你的输入,你不能在不知道确切语法的情况下简单地预处理你的JSON,要解决这个问题,你可以让GSON读取文件本身,例如:

http://www.java2blog.com/2013/11/gson-example-read-and-write-json.html

package org.arpit.java2blog;

import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.List;
import org.arpit.java2blog.pojo.Country;
import com.google.gson.Gson;

/*
* @Author : Arpit Mandliya
*/
public class GSONReadingFromFileExample {

public static void main(String[] args) {

Gson gson = new Gson();

try {

System.out.println("Reading JSON from a file");
System.out.println("----------------------------");

BufferedReader br = new BufferedReader(
new FileReader("E:\\file.json"));

//convert the json string back to object
Country countryObj = gson.fromJson(br, Country.class);

System.out.println("Name Of Country: "+countryObj.getName());


System.out.println("Population: "+countryObj.getPopulation());

System.out.println("States are :");

List<String> listOfStates = countryObj.getListOfStates();
for (int i = 0; i < listOfStates.size(); i++) {
System.out.println(listOfStates.get(i));
}

} catch (IOException e) {
e.printStackTrace();
}
}
}

关于java - Gson json解析不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27817182/

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