javascript - 如何正确使用 ES6 curry ？

Question

说我有，

const toUpperCase = word => word.toUpperCase();
const reverse = word => word.split('').reverse().join('')
const toLowerCase = word => word.toLowerCase();

我该怎么做，比如，

const transformWord = word => toUpperCase(word) => reverse(word) => toLowerCase(word)
console.log(transformWord('abcdefg')) // expected output: gfedcba

Answer 1

您可以使用函数数组并对其进行reduce:

const toUpperCase = word => word.toUpperCase();
const reverse = word => word.split('').reverse().join('')
const toLowerCase = word => word.toLowerCase();

const transformWord = word => [toUpperCase, reverse, toLowerCase].reduce((lastVal, fn) => fn(lastVal), word);
console.log(transformWord('abcdefg')) // expected output: gfedcba

还有 pipeline operator使这看起来更整洁的提案，但距离实现还有很长时间(仍处于第 1 阶段):

const transformWord = word => word |> toUpperCase |> reverse |> toLowerCase;