Java 游戏随机 id 数组

Question

你好，我有一个游戏，你可以四处走动，寻找发生了什么事的线索。我有一个map.txt，上面有代表每个 block 的数字。如果数量等于 5，则创建一个表。我想把线索摆在桌面上。我想知道 map 中创建了多少个表，并为每个表分配一个 id，但所有 id 都不能相同，并且 id 编号不能大于该 map 的表数量。这是到目前为止我的代码:

表类

public class TableWithClue {

    public int x, y;
    public boolean search = false;
    public Rectangle r, r1;

    public int time = 0;
    public int timer = 100;
    public int aftertime = 0;
    public int aftertimer = 100;

    public boolean foundsomething = false;
    public TableWithClue(int x, int y,int id) {

        this.x = x;
        this.y = y;

        r = new Rectangle(x - play.camx, y - play.camy, 20, 30);

    }

    public void tick() {
        r = new Rectangle(x - play.camx, y - play.camy, 20, 30);

        if (r.intersects(play.p.r)) {
                if(Keys.isPressed(Keys.e)){
                search = true;
                Sound.snap.play();


            }
        }
    }

    public void render(Graphics g) {
        Image img;

        if (search) {
            ImageIcon i62 = new ImageIcon("res/tiles/table1.png");
            img = i62.getImage();
            g.drawImage(img, x - play.camx, y - play.camy, null);

        } else {
            ImageIcon i62 = new ImageIcon("res/tiles/table1.png");
            img = i62.getImage();
            g.drawImage(img, x - play.camx, y - play.camy, null);

            if(r.intersects(play.p.r)){
            ImageIcon i162 = new ImageIcon("res/gui/openstuff.png");
            img = i162.getImage();
            g.drawImage(img, Comp.size.width /2 - 95, 50, null);

            g.setColor(Color.white);
            g.setFont(new Font("italic", Font.BOLD,15 ));
            g.drawString(" E to search ", Comp.size.width /2 - 32, 88);
            }
        }

        if(search && r.intersects(play.p.r)){
            if(time >=timer ){
                if(aftertime >= aftertimer){
                search = false;
                time= 0;
                aftertime = 0;
                }else{
                    aftertime++;
                }
            }else {
                time++;
            }



            g.setColor(Color.white);
            g.fillRect((int) play.p.x - 55, (int) play.p.y - 70, 120, 40);
            g.setColor(Color.black);
            g.drawRect((int) play.p.x - 55, (int) play.p.y - 70, 120, 40);

            if(time <timer && time != 0){
            g.setColor(Color.black);
            g.setFont(new Font("italic", Font.BOLD,15 ));
            g.drawString("Searching",(int) play.p.x - 30, (int) play.p.y - 55);
            }
            g.setColor(Color.gray);
            g.fillRect((int) play.p.x - 35, (int) play.p.y - 50, (80 * time) / timer, 10);
            g.setColor(new Color(0, 0, 0));
            g.drawRect((int) play.p.x - 35, (int) play.p.y - 50, 80, 10);

            if(aftertime<=aftertimer && time >= timer){
                g.setColor(Color.black);
                g.setFont(new Font("italic", Font.BOLD,12 ));
                g.drawString("Found Nothing",(int) play.p.x - 34, (int) play.p.y - 55);

            }
        }else{
            search = false;
        }


        if(play.debug){
            g.setColor(Color.red);
            g.drawRect(r.x, r.y, r.width, r.height);
            g.setColor(Color.yellow);
        }else{

        }

    }
}

这些表是在名为 block 的不同类中创建的:

 public void interactables() {
    if (id == 5) {
        screens.interactables.t1.add(new TableWithClue(x ,y));

    }
 }

这是 map 类:

public class map {

    private String path;
    private int width, height;

    private static block[][] blocks;

    private boolean open = false;;

    public Image i2;

    public map(String path) {

        this.path = path;

        loadMap();

    }

    public void loadMap() {
        InputStream is = this.getClass().getResourceAsStream(path);
        BufferedReader br = new BufferedReader(new InputStreamReader(is));

        try {
            width = Integer.parseInt(br.readLine());
            height = Integer.parseInt(br.readLine());

            blocks = new block[height][width];

            for (int y = 0; y < height; y++) {

                String line = br.readLine();

                String[] tokens = line.split("\\s+");

                for (int x = 0; x < width; x++) {
                    blocks[y][x] = new block(x * block.blocksize, y * block.blocksize, Integer.parseInt(tokens[x]));
                }
            }

        } catch (NumberFormatException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }

    public void draw(Graphics g) {

        for (int i = 0; i < blocks.length; i++) {
            for (int j = 0; j < blocks[0].length; j++) {
                if (blocks[i][j].x + 50 > play.camx && blocks[i][j].x - 50 < play.camx + Comp.size.width + 10 && blocks[i][j].y + 50 > play.camy && blocks[i][j].y - 50 < play.camy + Comp.size.height + 10) {

                blocks[i][j].render(g);
                }
            }
        }

    }

    public static block[][] getBlocks() {
        return blocks;

    }

    public void interact() {

        for (int i = 0; i < blocks.length; i++) {
            for (int j = 0; j < blocks[0].length; j++) {

                    blocks[i][j].interactables();

            }
        }

    }

    public void addNPC() {

        for (int i = 0; i < blocks.length; i++) {
            for (int j = 0; j < blocks[0].length; j++) {

                    blocks[i][j].NPC();

            }
        }

    }

}

提前谢谢您:)

Answer 1

首先，您需要将表的 ID 存储在 TableWithClue 类中。然后，您将需要在您的 block 类中使用 static int。该变量将存储下一个表的ID；每次，下一个 ID 都会传递给表的构造函数，然后变量就会递增。因此加载的第一个表将是表 0，第二个表将是表 1，依此类推。