java - 尽管数字太大，但仍在处理中(忽略，我已修复)

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import java.io.*;

导入java.util.*;

公开课CH04{

// Constants Declaration Section
//******************************

public static void main(String[] args) throws FileNotFoundException {
    // TODO Auto-generated method stub

    // Variables Declaration Section
    //******************************
    int  quarters;
    int  dimes;
    int  nickles;
    int  numberOfQuarters;
    int  numberOfDimes;
    int remainingAmount; 
    int numberOfNickles;
    int numberOfPennies;
    int maxSize;

    // Variables Initialization Section
    //*********************************
    Scanner data = new Scanner(new File("C:\\testing3.txt"));     //Reads from text file 
    ArrayList<Double> datadata = new ArrayList<Double>();    //Creates Array
    quarters = 25;
    dimes = 10;
    nickles = 5;
    maxSize = 10000;



    // Code Section
    //*************
    while(data.hasNextDouble())    //Retrieves data from text file and places it in array
    {
        datadata.add(data.nextDouble());  //Retrieves data from text file and places it in array
    }

    for (int i = 0; i < datadata.size(); i++)  //Loops through the data
    {
        double value = datadata.get(i);   //returns number found in file as a double 'value' then runs it through the calculator
        System.out.println(value);

        while(value > maxSize) //If value is greater than 10,000, it will be skipped and not read through the calculator
        {

        }

        remainingAmount = (int)Math.ceil((value) * 100);      //multiplies value by 100

        numberOfQuarters = remainingAmount / quarters;   //divides value by 25
        remainingAmount = remainingAmount % quarters;    //returns the remaining value 

        numberOfDimes = remainingAmount / dimes;    //divides the remaining value by 10
        remainingAmount = remainingAmount % dimes;  //returns the remaining value of that

        numberOfNickles = remainingAmount / nickles;  //divides the remaining value from dimes by 5
        remainingAmount = remainingAmount % nickles;  //returns remaining value

        numberOfPennies = remainingAmount;   //divides remaining value by 1


        System.out.print("Your amount of $" + value + " consists of: \n" + numberOfQuarters +            //prints out the amount of quarters, dimes, nickels, pennies
                " quarteres, " + numberOfDimes + " dimes, " + numberOfNickles + " nickles, and " +       //that make up each value found inside the file.
                  numberOfPennies + " pennies");

        System.out.print("\n\n");

    }



    //Output Section
    //**************




    //Resource Cleaning
    //*****************
    data.close();

}

}

**Output: 

10001.0值太大，无法处理 10001.0您的 $10001.0 金额包括:40004 个 25 美分、0 个一角、0 个镍币和 0 个便士

9755.35您的 9755.35 美元金额包括:39021 25 美分、1 角硬币、0 镍币和 0 便士

875.4您的 875.4 美元金额包括:3501 25 美分、1 角硬币、1 镍币和 0 便士

78.99您的 78.99 美元金额包括:315 25 美分、2 角硬币、0 镍币和 4 便士

5.0您的 5.0 美元金额包括:20 个 25 美分、0 个 10 分、0 个 5 分币和 0 个便士

0.7您的 0.7 美元金额包括:2 个 25 美分、2 个 10 分、0 个镍币和 0 个便士

正在使用的值:[10001.0、9755.35、875.4、78.99、5.0、0.7] **

由于某种原因，输出的斜体部分我收到的钱少了 1 便士。这让我很困惑，因为其余的输出是正确的。

我的文本值中的值为:

10,001.00 -
9,755.35 -
875.40 -
78.99 -
5.00 -
0.70

Answer 1

我不会写代码本身。作为一个例子，我猜它是手工制作的。调试此类问题的一般经验法则是:查看最后或查看开头。除法工作正常，因此它必须在一开始就发生，这就是您的值被转换为 int 的地方。如果您检查值 * 100 的乘积结果，那么您会看到 7898.999999999999，而不是您预期的 7899。您应该使用 Math.ceil 来获取正确的值，如下所示:

 int result = (int)Math.ceil(value * 100);