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java - 简单的密码和 I/O

转载 作者:行者123 更新时间:2023-12-01 11:54:47 25 4
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这段代码应该从源文件中读取一个字符;转换为 ASCII int 值;加 1;转换回字符;写入目标文件。

我的目标文件中没有显示任何内容。

现在,我并不担心获得大于 255 的 ASCII 值或效率。

import java.io.*;

public class ReadAFile {

public static void main(String[] args) {

try {
File myFile = new File("source.txt");

FileReader fileReader = new FileReader(myFile);

BufferedReader reader = new BufferedReader(fileReader);

int character;

int shift = 1;

while ((character = reader.read()) != -1) {

character = (int) reader.read() + shift;

WriteAFile(Character.toString((char) character));


}

reader.close();

} catch (Exception ex) {
ex.printStackTrace();
}

}

public static void WriteAFile(String line) {

try {
FileWriter writer = new FileWriter("destination.txt");

writer.write(line);

writer.close();
} catch (IOException ex) {
ex.printStackTrace();
}

}

}

最佳答案

只是将 @Deepak 放入代码中是说:

 public static void main(String[] args) 
{
try
{
File myFile = new File("c:\\temp\\source.txt"));
File outputFile = new File("c:\\temp\\output.txt");
FileWriter writer = new FileWriter(outputFile);
FileReader fileReader = new FileReader(myFile);
BufferedReader reader = new BufferedReader(fileReader);

try
{
int character;
int shift = 1;

while ((character = reader.read()) != -1)
{
character = (int) reader.read() + shift;
writer.write(Character.toString((char) character));
}
}
finally
{
writer.close();
reader.close();
}
}
catch (Exception ex)
{
ex.printStackTrace();
}
}

还要确保指定输出路径。

关于java - 简单的密码和 I/O,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28530584/

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