java - 创建 do-while 循环来提示用户是否要输入另一个 ISBN

Question

因此，作为我的类(class)项目，我需要编写一个程序，让用户输入 ISBN 号码的前 n 位数字，并以第十位数字进行响应。我一直在无休止地寻找一些东西，让我的程序询问用户是否要再次运行该程序，然后在用户输入"is"或“Y”时再次运行该程序。我发现的方法不起作用，通常它只是循环“您想输入另一个 ISBN 吗？”而不实际让他们输入 ISBN。我的代码在下面，谢谢大家的帮助!

import java.util.Scanner;
public class ISBNCheckSum {

    public static void main(String[] args) 
    {
        Scanner keyboard = new Scanner(System. in );
        // limiter 
        int isbn10 = 9;
        // to take in response of user
        long userResponse;
        // accumulator 
        int ISBnNum = 1;
        //current count of ISBN
        long isbnCount = 0;
        // This is used to multiply the userresponse by 1,2,3... up to 9
        int multiplier = 1;

        while (ISBnNum <= isbn10) 
        {
            System.out.println("Please ISBN number  " + ISBnNum);
            //to enter the User response
            userResponse = keyboard.nextInt();
            //Multiply the user response by multiplier variable
            userResponse = userResponse * multiplier;
            //add to accumulator 
            ISBnNum = ISBnNum + 1;
            // put user into final answer
            isbnCount = isbnCount + userResponse;
            // increase multiplier
            multiplier = multiplier + 1;
        }

        long checkSum;
        checkSum = isbnCount % 11;
        System.out.println(checkSum);
    }
}
}

Answer 1

尝试这样的事情(我已经更改了 iSBnNum 变量名称):

    boolean askAgain = true;
    while (askAgain) {
        iSBnNum = 1;
        while (iSBnNum <= isbn10) {
            System.out.println("Please ISBN number  " + iSBnNum);
            // to enter the User response
            userResponse = keyboard.nextInt();
            // Multiply the user response by multiplier variable
            userResponse = userResponse * multiplier;
            // add to accumulator
            iSBnNum = iSBnNum + 1;
            // put user into final answer
            isbnCount = isbnCount + userResponse;
            // increase multiplier
            multiplier = multiplier + 1;
        }

        System.out.println("Ask again (Y/N)?");
        String answer = keyboard.next();

        askAgain = answer.equalsIgnoreCase("Y");
    }