Java 忽略用户输入中的空格

Question

基本上，我正在制作一个凯撒密码程序，用于加密或解密用户输入的消息。但是，如果用户在消息中输入空格(例如 Stack Overflow)，它将对空格和字母执行加密或解密偏移过程，显然我不希望它这样做。我希望它忽略空格并将其打印在加密或解密的消息中。

这是我的代码:

    Scanner myinput = new Scanner(System.in);   
    String plain;
    String encrypted; 
    char chars[] = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z', ' ', 'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z', ' ','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z', ' ','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z', ' '};

    System.out.println("Please enter your message."); 
    plain = myinput.nextLine().toUpperCase(); 
    myinput.close(); 

    char[] plaintext = plain.toCharArray(); 
    if(plain.isEmpty()) { 
            System.out.println("You need to give me a message to encrypt.");
    }

    for(int c = 0;c < plaintext.length;c++) { 
        for(int p = 0 ; p < 105;p++) { 
            if(p <= 100) { 
                if(plaintext[c] == chars[p]) {
                    plaintext[c] = chars[p + offset];
                        break;
                    }  
                }
            else if(plaintext[c] == chars[p]) {
                plaintext[c] = chars[p - 81];
            }
        }
    }
    encrypted = String.valueOf(plaintext);
    return encrypted; 

Answer 1

for(int p = 0 ; p < 105; p++) {
    if (plaintext[p] == ' ') continue;

这就是保持空格不变所需的全部内容，还可以从 chars 数组中删除它们