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java - 如何计算快速排序中的比较和交换?

转载 作者:行者123 更新时间:2023-12-01 11:45:57 24 4
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public class IntQuickSorter
{
public static int numOfComps = 0,
numOfSwaps = 0;

public static void main(String[] args)
{
// Create an int array with test values.
int[] values = { 1, 2, 3, 4, 5, 6 };
//int[] values = { 5, 1, 3, 6, 4, 2 };
//int[] values = { 5, 7, 2, 8, 9, 1 };

System.out.println("\n\nQuick Sort:");

// Display the array's contents.
System.out.println("\nOriginal order: ");
for (int element : values)
System.out.print(element + " ");

// Sort the array.
quickSort(values);

//System.out.println("\n\nNumber of comps = " + numOfComps);
//System.out.println("Number of swaps = " + numOfSwaps);

// Display the array's contents.
System.out.println("\nSorted order: ");
for (int element : values)
System.out.print(element + " ");

System.out.println();
}

public static void quickSort(int array[])
{
doQuickSort(array, 0, array.length - 1);
System.out.println("\n\nNumber of comps = " + numOfComps);
System.out.println("Number of swaps = " + numOfSwaps);
}

private static void doQuickSort(int array[], int start, int end)
{
int pivotPoint;

if (start < end)
{
numOfComps++;

// Get the pivot point.
pivotPoint = partition(array, start, end);

// Sort the first sub list.
doQuickSort(array, start, pivotPoint - 1);

// Sort the second sub list.
doQuickSort(array, pivotPoint + 1, end);
}
}

private static int partition(int array[], int start, int end)
{
int pivotValue; // To hold the pivot value
int endOfLeftList; // Last element in the left sub list.
int mid; // To hold the mid-point subscript

// Find the subscript of the middle element.
// This will be our pivot value.
mid = (start + end) / 2;

// Swap the middle element with the first element.
// This moves the pivot value to the start of
// the list.
swap(array, start, mid);

// Save the pivot value for comparisons.
pivotValue = array[start];

// For now, the end of the left sub list is
// the first element.
endOfLeftList = start;

// Scan the entire list and move any values that
// are less than the pivot value to the left
// sub list.
for (int scan = start + 1; scan <= end; scan++)
{

if (array[scan] < pivotValue)
{
endOfLeftList++;
swap(array, endOfLeftList, scan);

numOfSwaps ++;
}
numOfComps++;
}

// Move the pivot value to end of the
// left sub list.
swap(array, start, endOfLeftList);

// Return the subscript of the pivot value.
return endOfLeftList;
}

private static void swap(int[] array, int a, int b)
{
int temp;

temp = array[a];
array[a] = array[b];
array[b] = temp;
}
}

如何用 Java 编写这个快速排序程序来计算比较次数和交换次数?在我现在有交换代码的地方,即使使用已排序的数字数组,它也会对交换进行计数,但它不应该这样做。比较代码是否位于正确的位置?感谢您的帮助。

最佳答案

Where I have the swap code now, it counts swaps even with a sorted array of numbers and it shouldn't.

这不太准确。已排序的数组与快速排序进行一些交换,这就是旋转和分区的工作原理。这是使用排序列表的典型快速排序的动画。 Animation gist

quicksort-on-sorted

此外,删除此比较:

if (start < end)
{
numOfComps++;

因为这不是数组中两个事物的“关键比较”,只是索引的“关键比较”。
除此之外,您的比较和交换看起来是在正确的位置。

关于java - 如何计算快速排序中的比较和交换?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29124070/

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