java - 如何获取pptx4j中slideLayout的名称？

Question

我使用 pptx4j 加载现有演示文稿，并且需要每个布局的名称。使用以下代码，我认为它应该可以工作:

    // loading layout
    SlideLayoutPart layoutPart = null;
    try {
        PartName partName = new PartName("/ppt/slideLayouts/slideLayout1.xml");
        layoutPart = (SlideLayoutPart) presentationMLPackage.getParts().getParts().get(partName);
        // get name
        String layoutName = layoutPart.getContents().getCSld().getName();
        log.debug("LayoutName: " + layoutName);
    } catch (InvalidFormatException e) {
        log.error("Error - Could not load layout: " + e);
    } catch (Docx4JException e) {
        log.error("Error - Could not get layoutName: " + e);
    }

但是我收到 layoutPart.getJaxbElement() 的 NullPointerException。这是错误的方式还是为什么我会收到此错误？

整个异常:

java.lang.IllegalArgumentException: Unknown type of result: class javax.xml.transform.dom.DOMResult 
        at net.sf.saxon.event.SerializerFactory.getReceiver(SerializerFactory.java:154)
        at net.sf.saxon.IdentityTransformerHandler.startDocument(IdentityTransformerHandler.java:94)
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.DomLoader$State.<init>(DomLoader.java:67)
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.DomLoader.startElement(DomLoader.java:102)
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.ProxyLoader.startElement(ProxyLoader.java:45)
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext._startElement(UnmarshallingContext.java:486)
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.startElement(UnmarshallingContext.java:465)
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.InterningXmlVisitor.startElement(InterningXmlVisitor.java:60)
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.SAXConnector.startElement(SAXConnector.java:135)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:229)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:266)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:235)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:266)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:235)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:266)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:235)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:266)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:235)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.scan(DOMScanner.java:112)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.scan(DOMScanner.java:95)
        at com.sun.xml.internal.bind.unmarshaller.DOMScanner.scan(DOMScanner.java:88)
        at com.sun.xml.internal.bind.v2.runtime.BinderImpl.associativeUnmarshal(BinderImpl.java:146)
        at com.sun.xml.internal.bind.v2.runtime.BinderImpl.unmarshal(BinderImpl.java:117)
        at org.docx4j.openpackaging.parts.JaxbXmlPartXPathAware.unmarshal(JaxbXmlPartXPathAware.java:316)
        at org.docx4j.openpackaging.parts.JaxbXmlPart.getJaxbElement(JaxbXmlPart.java:130)
        at pptx4j.PPTXConverter.create(Converter.java:83)
        at Starter.main(Starter.java:17)
Exception in thread "main" java.lang.NullPointerException
        at pptx4j.PPTXConverter.create(PPTXConverter.java:83)
        at Starter.main(Starter.java:17)

作为补充 slideLayout1.xml 与内容一起存在，我可以使用它来创建新幻灯片。

希望有人能给我提示。如果需要其他信息，请询问。

更新

我使用的是 3.0.1 版本，所以我更新到 3.2.1 并更改了我的代码。现在 NullPointerException 消失了，但我仍然收到 layoutPart.getContents().getCSld() 的 IllegalArgumentException:

INFO  JaxbXmlPart - Lazily unmarshalling /ppt/slideLayouts/slideLayout1.xml
INFO  JaxbXmlPartXPathAware - For org.docx4j.openpackaging.parts.PresentationML.SlideLayoutPart, unmarshall via binder
DEBUG JaxbXmlPartXPathAware - info: com.sun.xml.internal.bind.v2.runtime.BinderImpl
ERROR JaxbXmlPartXPathAware - Unknown type of result: class javax.xml.transform.dom.DOMResult
java.lang.IllegalArgumentException: Unknown type of result: class javax.xml.transform.dom.DOMResult

Answer 1

问题是我使用的库之间存在某些依赖关系。不幸的是，我不能说是哪个图书馆。现在仅适用于 saxon 和 docx4j。如果我可以重现我的问题，我会将其添加到此处。

@JasonPlutext 感谢您的回答和提示!