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Java 新手需要有关如何显示移动按钮的建议

转载 作者:行者123 更新时间:2023-12-01 11:44:15 24 4
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当文本输入到文本屏幕时,我试图让按钮在屏幕上移动,我已经想出了这段代码,但当我真正想看到它移动时,它最终只显示结束位置:

if (TextDemo.textField.getText().equals("moveCar"))
{

for (int x = 0; x<250;x++)
{

try
{
Thread.sleep(10);
}catch
(InterruptedException ex) {
Thread.currentThread().interrupt();
}
jOneCarOne.setLocation(130 + x, 210);
}
}

我确实有一个重绘方法,但它没有什么区别,任何帮助将不胜感激

最佳答案

看看这个 MCVE :

public class TextDemo {
static JFrame frame;
static JTextField textField;
static Component jOneCarOne;

public static void main(String[] args) {
frame = new JFrame();
frame.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);
frame.setLayout(null);
frame.setSize(640, 480);
frame.setLocationRelativeTo(null);

textField = new JTextField();
textField.setBounds(0, 0, 640, 20);
textField.addActionListener(getTextFieldAction());
frame.add(textField);

jOneCarOne = new JLabel("<html><b><u>CAR");
jOneCarOne.setBounds(130, 210, 64, 64);
frame.add(jOneCarOne);

frame.setVisible(true);
}

static ActionListener getTextFieldAction() {
return new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
if (TextDemo.textField.getText().equals("moveCar")) {
moveCar();
}
}
};
}

static void moveCar() {
final int endX = jOneCarOne.getX() + 250;
Timer timer = new Timer(true);
timer.scheduleAtFixedRate(new TimerTask() {
//execute this every 10 ms
@Override
public void run() {
if(jOneCarOne.getX() == endX) {
//break condition, cancel periodic execution
this.cancel();
}
jOneCarOne.setLocation(jOneCarOne.getX() + 1, jOneCarOne.getY());
}
}, 0, 10);
}
}

关于Java 新手需要有关如何显示移动按钮的建议,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29282540/

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