AJAX成功不执行

Question

我有一个使用 ajax 提交的表单。提交总是成功的，但我的成功声明中的任何内容都没有执行。我让我的 Django View 返回一个 status = 200，但仍然没有。谁能说出为什么这不执行？在我的终端中，它显示我有一个损坏的管道错误，但我已经读到我可以忽略我的开发服务器上的那些。不确定这是否与此有关。

我的表格:

<form onsubmit="createAdd({{ newID }}, {{ user.get_profile.id }})" class="form-horizontal create" method="post">{% csrf_token %}
 <div class="control-group">
    <label class="control-label" for="newName">Name*</label>
    <div class="controls">
      <input type="text" name="newName" id="name" required>
   </div>
  </div>
  <div class="control-group">
    <div class="controls">
      <button type="submit" class="btn btn-primary" value="Create"><i class="icon-wrench icon-white"> </i> Create </button>
    </div>
  </div>
</form>

我的 AJAX 函数:

function createAdd(event, user){  // Creates a custom event and automatically gives creator ownership
    var name = document.getElementById('name').value;
    var loc = document.getElementById('loc').value;
    var start = document.getElementById('datepicker').value;
    var end = document.getElementById('datepicker2').value;
    var tags = document.getElementById('tags').value;
    var jqxhr = $.ajax( "/eventsearch/eventsearch/createCustom/", {
        type: "POST", 
        data: {name: name, loc: loc, start: start, end: end, tags: tags, event_id: event, profile: user}
    })
    .done(function() { alert("success"); })
    .fail(function() { alert("hello") })
}

我实际上并不想访问 Google，我只是想让它重定向到某个地方。如果我在其中放置一个 alert，它也不会执行。

我的全貌:

@login_required
def createCustom(request):

    newID = len(customEvent.objects.all())
    newName = request.POST['name']
    newLoc = request.POST['loc']
    newStart = request.POST['start']
    newEnd = request.POST['end']
    newTags = request.POST['tags']
    newURL = "/eventc/" + str(newID)

    e = customEvent(event_id = newID, title = newName, start = newStart, end = newEnd, location = newLoc, tags = newTags, url = newURL)
    e.save()

    event_id = request.POST['event_id']
    user = request.POST['profile']
    event = customEvent.objects.get(event_id = event_id)
    user = Profile.objects.get(id = user)
    user.ownedEvent.add(event)

    return HttpResponse('', content_type="application/json")

提前致谢!

Answer 1

您需要返回答案 - JSON
例如

def answer(request):    
    # same you code
    payload = {'success': True}
    return HttpResponse(json.dumps(payload), content_type='application/json')