java - 有时需要在扫描仪中多次输入输入才能工作？

Question

嗨，我对编程很陌生。我最近开始了一个文本“逃离房间”类型的游戏，当我运行它时，它无法正常工作。我必须多次输入输入才能真正运行下一件事。

import static java.lang.System.*;
import java.util.Scanner;

public class RoomEscape {
public static void main(String args[]) throws InterruptedException{

    Scanner scan = new Scanner(System.in);

    out.println("Welcome to Room Escape.");
    out.println("Please type \"start\" to continue");
    String sta = scan.nextLine();
    if (sta.equals("start"))
        game();
}

public static void game() throws InterruptedException {
    boolean run = true;
    int ori = 1;
    Scanner scan = new Scanner(System.in);
    String ew = scan.nextLine();
    String input = scan.next();

    out.println("You wake up in a room.");
    Thread.sleep(1000);
    out.println("You don't know how you got there.");
    Thread.sleep(1000);
    out.println("You feel dizzy, tired, and hungry.");
    Thread.sleep(1000);
    out.println("Your objective is to leave the room");
    Thread.sleep(1000);
    out.println("Type \"help\" for your commands and inventory at any time.");

    while (run) {
        if (input.equalsIgnoreCase("help")) {
            out.println("Commands are: \"right\" to turn right");
            out.println("\"left\" to turn left");
            out.println("\"examine\" to look more closely at an object");
            out.println("\"pick up\" to put an object in your inventory");
        } 
        else if (input.equalsIgnoreCase("right")) {
            ori++;

        }

    }
}}

运行上面的代码时，有时需要输入两到三次“start”才能运行 game()。感谢您的帮助!

Answer 1

你的问题是，当你在 game() 中时，你会在游戏开始之前扫描输入，而不是在主循环内。你有

String ew = scan.nextLine();
String input = scan.next();

我不确定你为什么要使用ew。

直接放

String input = scan.nextLine();

在 while 循环的开头并将它们从游戏函数的开头取出。