java - ObjectInputStream.readObject() 抛出 NotSerializedException

Question

我在通过 ArrayList<People> 时遇到了一些问题(其中包含大图片)超过使用 Bundle 的 Activity 。我失败了，因为Bundle有 1MB 限制。经过一些研究，我发现序列化对象并将其保存到文件中会更好，所以我创建了这个类:

public class BundlePeople {

    public static long packPeople(Context context, List<People> people) {
        long timeToken = System.currentTimeMillis();
        String fileName = "temp_" + Long.toString(timeToken);
        try {
            FileOutputStream fos = context.openFileOutput(fileName, Context.MODE_PRIVATE);
            ObjectOutputStream os = new ObjectOutputStream(fos);
            os.writeObject(people);
            os.close();
            fos.close();
        } catch (IOException e) {
            Log.e("BundlePeople", e.getMessage());
        }

        return timeToken;
    }

    public static List<People> unpackPeople(Context context, long id) {
        List<People> list = new ArrayList<>();

        String fileName = "temp_" + Long.toString(id);
        try {
            FileInputStream fis = context.openFileInput(fileName);
            ObjectInputStream is = new ObjectInputStream(fis);
            list.addAll((List<People>) is.readObject()); //Here I get NotSerializableException on second call
            is.close();
            fis.close();
        } catch (IOException | ClassNotFoundException e) {
            Log.e("BundlePeople", e.getMessage());
        }

        return list;
    }
}

它可以工作一次，但是当我尝试再次使用它时，它会抛出 NotSerializableExcpetion

第一次通话:

传递(FirstActivity.java)

Bundle bundle = new Bundle();
bundle.putLong("peopleFileId", BundlePeople.packPeople(FirstActivity.this, listPeople));
Intent i = new Intent(FirstActivity.this, SecondActivity.class);
i.putExtras(bundle);    
startActivityForResult(i.setFlags(SecondActivity.FLAG_SELECT), 0);

接收(SecondActivity.java)

long id = getIntent().getExtras().getLong("peopleFileId");
list = new ArrayList<>();
list.addAll(BundlePeople.unpackPeople(getApplicationContext(), id));

目前工作正常，问题是当我第二次使用它时:

第二次通话:

传递(SecondActivity.java)

Intent i = new Intent();
Bundle b = new Bundle();
b.putLong("peopleFileId", BundlePeople.packPeople(SecondActivity.this, list));
i.putExtras(b);
setResult(REQUEST_PEOPLE, i);
finish();

接收(FirstActivity.java [onActivityResult()])

List<People> list = BundlePeople.unpackPeople(
                        getApplicationContext(), data.getExtras().getLong("peopleFileId"));

我的列表是 null因为 BundlePeople 上抛出异常在第一个代码指示的行处。

异常消息:Read an exception; java.io.NotSerializableException: br.com.something.activities.SecondActivity$1

我的问题是，为什么我会收到此异常？这是通过 Activity 传递大型对象的更好方法吗？如果是的话，这里出了什么问题？

编辑

People.java

public class People implements Serializable {

    private static final long serialVersionUID = -9171517741542003990L;

    private Integer id;
    private String name;
    private BitmapSerializable image;

    public BitmapSerializable getImage() {
        return image;
    }

    public void setImage(BitmapSerializable image) {
        this.image = image;
    }

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }
}

Answer 1

你:

• 序列化了不可序列化的对象；
• 忽略异常；
• 保存文件；和
• 尝试对其进行反序列化。

幸运的是，在这种情况下，Java 将异常写入文件，并在反序列化时抛出它。异常消息为您提供相关类的名称。

但它不应该走到这一步。