matplotlib - 具有相同标签的不同散点图标记

Question

我遇到了与 Matplotlib, legend with multiple different markers with one label 类似的问题.由于这个问题Combine two Pyplot patches for legend，我能够实现以下目标.

fig = pylab.figure()
figlegend = pylab.figure(figsize=(3,2))
ax = fig.add_subplot(111)
point1 = ax.scatter(range(3), range(1,4), 250, marker=ur'$\u2640$', label = 'S', edgecolor = 'green')
point2 = ax.scatter(range(3), range(2,5), 250, marker=ur'$\u2640$', label = 'I', edgecolor = 'red')
point3 = ax.scatter(range(1,4), range(3),  250, marker=ur'$\u2642$', label = 'S', edgecolor = 'green')
point4 = ax.scatter(range(2,5), range(3), 250, marker=ur'$\u2642$', label = 'I', edgecolor = 'red')
figlegend.legend(((point1, point3), (point2, point4)), ('S','I'), 'center',  scatterpoints = 1, handlelength = 1)
figlegend.show()
pylab.show()

但是，我的两个(金星和火星)标记在图例中重叠。我尝试使用句柄长度，但这似乎没有帮助。任何建议或意见都会有所帮助。

Answer 1

一种可能的解决方法是在第一列中创建一个带有空白标签的两列图例:

figlegend.legend((point1, point2, point3, point4), (' ', ' ', 'S', 'I'), 
                 'center',  scatterpoints = 1, ncol = 2)