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java - JTable 获取值时出错

转载 作者:行者123 更新时间:2023-12-01 11:19:27 25 4
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我无法解决此错误,它总是在线显示“无法访问的语句”:

 int row = e.getFirstRow()

它建议分割声明,但是,即使在那之后,错误在行 "e.getFirstRow()" 上仍然保持不变:

import javax.swing.event.TableModelEvent;
import javax.swing.event.TableModelListener;
import javax.swing.table.DefaultTableModel;
import javax.swing.table.TableModel;

public class View extends javax.swing.JFrame implements TableModelListener{
int row;
DefaultTableModel model;

public View() {
initComponents();

model = (DefaultTableModel) jTable2.getModel();
model.addRow(new Object[]{"abc","abc","abc","abc"});
model.addRow(new Object[]{"abc","abc","abc","abc"});
model.addRow(new Object[]{"abc","abc","abc","abc"});
model.addRow(new Object[]{"abc","abc","abc","abc"});

model.addTableModelListener(this);
}


@SuppressWarnings("unchecked")
// <editor-fold defaultstate="collapsed" desc="Generated Code">
private void initComponents() {

jScrollPane2 = new javax.swing.JScrollPane();
jTable2 = new javax.swing.JTable();

setDefaultCloseOperation(javax.swing.WindowConstants.EXIT_ON_CLOSE);

jTable2.setModel(new javax.swing.table.DefaultTableModel(
new Object [][] {

},
new String [] {
"A", "B", "C", "D"
}
) {
Class[] types = new Class [] {
java.lang.String.class, java.lang.String.class, java.lang.String.class, java.lang.String.class
};

public Class getColumnClass(int columnIndex) {
return types [columnIndex];
}
});
jScrollPane2.setViewportView(jTable2);

javax.swing.GroupLayout layout = new javax.swing.GroupLayout(getContentPane());
getContentPane().setLayout(layout);
layout.setHorizontalGroup(
layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING)
.addComponent(jScrollPane2, javax.swing.GroupLayout.Alignment.TRAILING, javax.swing.GroupLayout.DEFAULT_SIZE, 546, Short.MAX_VALUE)
);
layout.setVerticalGroup(
layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING)
.addComponent(jScrollPane2, javax.swing.GroupLayout.PREFERRED_SIZE, 202, javax.swing.GroupLayout.PREFERRED_SIZE)
);

pack();
}// </editor-fold>


public static void main(String args[]) {

java.awt.EventQueue.invokeLater(new Runnable() {
public void run() {
new View().setVisible(true);
}
});
}

// Variables declaration - do not modify
private javax.swing.JScrollPane jScrollPane2;
private javax.swing.JTable jTable2;
// End of variables declaration

@Override
public void tableChanged(TableModelEvent e) {
throw new UnsupportedOperationException("Not supported yet.");

row = e.getFirstRow();
int column = e.getColumn(); //<<<--------------- This LINE
TableModel model = (TableModel)e.getSource();
String columnName = model.getColumnName(column);
Object data = model.getValueAt(row, column);
}
}

最佳答案

问题出在这一行(在无法访问的那一行之前):

throw new UnsupportedOperationException("Not supported yet."); 

你的程序永远不会执行该语句下面的内容,因为它总是抛出异常。编译器会告诉你“不可达语句”永远不会被执行。

删除throw ...语句,你就可以上路了!

关于java - JTable 获取值时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31432950/

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