java - 此 KnockKnockProtocol 类的构造函数代码中的 Java bug 在哪里？

Question

我正在研究以下名为 KnockKnockServer and KnockKnockClient. 的客户端/服务器代码它还有一个名为 KnockKnockProtcol 的辅助类。 ，它负责 KnockKnock 笑话的顺序。

我想修改它，以便您可以在特定的笑话处启动程序。现在的情况是，你必须从第一个笑话开始。

这是对 KnockKnockProtocol 的尝试:

public class KnockKnockProtocol {

    int ourstep;

    public KnockKnockProtocol (int step) {
        this.ourstep = step;
    }

    private static final int WAITING = 0;
    private static final int SENTKNOCKKNOCK = 1;
    private static final int SENTCLUE = 2;
    private static final int ANOTHER = 3;

    private static final int NUMJOKES = 5;

    private int state = WAITING;
    int currentJoke = ourstep;  //we initialize the step here

    private String[] clues = { "Turnip", "Little Old Lady", "Atch", "Who", "Who" };
    private String[] answers = { "Turnip the heat, it's cold in here!",
                                 "I didn't know you could yodel!",
                                 "Bless you!",
                                 "Is there an owl in here?",
                                 "Is there an echo in here?" };

    public String processInput(String theInput) {
        String theOutput = null;

        if (state == WAITING) {
            theOutput = "Knock! Knock!";
            state = SENTKNOCKKNOCK;
        } else if (state == SENTKNOCKKNOCK) {
            if (theInput.equalsIgnoreCase("Who's there?")) {
                theOutput = clues[currentJoke];
                state = SENTCLUE;
            } else {
                theOutput = "You're supposed to say \"Who's there?\"! " +
                "Try again. Knock! Knock!";
            }
        } else if (state == SENTCLUE) {
            if (theInput.equalsIgnoreCase(clues[currentJoke] + " who?")) {
                theOutput = answers[currentJoke] + " Want another? (y/n)";
                state = ANOTHER;
            } else {
                theOutput = "You're supposed to say \"" + 
                clues[currentJoke] + 
                " who?\"" + 
                "! Try again. Knock! Knock!";
                state = SENTKNOCKKNOCK;
            }
        } else if (state == ANOTHER) {
            if (theInput.equalsIgnoreCase("y")) {
                theOutput = "Knock! Knock!";
                if (currentJoke == (NUMJOKES - 1))
                    currentJoke = 0;
                else
                    currentJoke++;
                state = SENTKNOCKKNOCK;
            } else {
                theOutput = "Bye.";
                state = WAITING;
            }
        }
        return theOutput;
    }
}

在 Server 类中，我这样调用 KnockKnockProtocol:

    /* omitting boilerplate code */
    String inputLine, outputLine;

    // Initiate conversation with client
    KnockKnockProtocol kkp = new KnockKnockProtocol(2);
    outputLine = kkp.processInput(null);
    out.println(outputLine);

    while ((inputLine = in.readLine()) != null) {
        outputLine = kkp.processInput(inputLine);
        out.println(outputLine);
        if (outputLine.equals("Bye."))
            break;

问题是，当我运行代码时，我总是从“萝卜”笑话开始。如何才能从笑话列表中的任意笑话开始？我可以看到这个笑话是由 clues 数组控制的，但之后我就看不到它了。谢谢

Answer 1

如果您查看 KnockKnockProtocol 构造函数的输入，您会发现它通过 this.ourstep 直接影响 currentJoke 计数器，即然后用于引用 clues 数组。

因此，要从不同的位置开始，您可以在程序开头的构造函数中传递不同的数字。

希望有帮助!