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r - 提取列表元素并连接成 r 中的字符串

转载 作者:行者123 更新时间:2023-12-01 11:16:26 24 4
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使用下面的变量列表,我想对所有组合,将变量连接成一个由“+”分隔的字符串

l_ALLVar_list <- c("a","b","c","d","z1","z2","z3") 

我有生成 127 种组合的代码

all_combos=do.call("c", lapply(seq_along(l_ALLVar_list), function(i) combn(l_ALLVar_list, i, FUN = list)))

以66位为例

> all_combos[66]
[[1]]
[1] "a" "b" "c" "z2"

我希望能够将索引 66 处的这些元素连接到字符串 a+b+c+z2 中

我试过了

str_c(c(lol[66]),collapse=',')

但它回来了

c(\"weight\", \"length\", \"wheel_base\", \"city_mpg\")

paste(all_combos[66], collapse = '')

再次产生相同的结果

任何帮助将不胜感激

最佳答案

您可以使用 combn 中的 FUN 参数在一次调用中粘贴 l_ALLVar_list 的所有组合,消除对 all_combos 列表的需要。

unlist(lapply(seq_along(l_ALLVar_list), combn, x=l_ALLVar_list, paste, collapse="+"))
# [1] "a" "b" "c" "d" "z1"
# [6] "z2" "z3" "a+b" "a+c" "a+d"
# [11] "a+z1" "a+z2" "a+z3" "b+c" "b+d"
# [16] "b+z1" "b+z2" "b+z3" "c+d" "c+z1"
# [21] "c+z2" "c+z3" "d+z1" "d+z2" "d+z3"
# [26] "z1+z2" "z1+z3" "z2+z3" "a+b+c" "a+b+d"
# [31] "a+b+z1" "a+b+z2" "a+b+z3" "a+c+d" "a+c+z1"
# [36] "a+c+z2" "a+c+z3" "a+d+z1" "a+d+z2" "a+d+z3"
# [41] "a+z1+z2" "a+z1+z3" "a+z2+z3" "b+c+d" "b+c+z1"
# [46] "b+c+z2" "b+c+z3" "b+d+z1" "b+d+z2" "b+d+z3"
# [51] "b+z1+z2" "b+z1+z3" "b+z2+z3" "c+d+z1" "c+d+z2"
# [56] "c+d+z3" "c+z1+z2" "c+z1+z3" "c+z2+z3" "d+z1+z2"
# [61] "d+z1+z3" "d+z2+z3" "z1+z2+z3" "a+b+c+d" "a+b+c+z1"
# [66] "a+b+c+z2" "a+b+c+z3" "a+b+d+z1" "a+b+d+z2" "a+b+d+z3"
# [71] "a+b+z1+z2" "a+b+z1+z3" "a+b+z2+z3" "a+c+d+z1" "a+c+d+z2"
# [76] "a+c+d+z3" "a+c+z1+z2" "a+c+z1+z3" "a+c+z2+z3" "a+d+z1+z2"
# [81] "a+d+z1+z3" "a+d+z2+z3" "a+z1+z2+z3" "b+c+d+z1" "b+c+d+z2"
# [86] "b+c+d+z3" "b+c+z1+z2" "b+c+z1+z3" "b+c+z2+z3" "b+d+z1+z2"
# [91] "b+d+z1+z3" "b+d+z2+z3" "b+z1+z2+z3" "c+d+z1+z2" "c+d+z1+z3"
# [96] "c+d+z2+z3" "c+z1+z2+z3" "d+z1+z2+z3" "a+b+c+d+z1" "a+b+c+d+z2"
#[101] "a+b+c+d+z3" "a+b+c+z1+z2" "a+b+c+z1+z3" "a+b+c+z2+z3" "a+b+d+z1+z2"
#[106] "a+b+d+z1+z3" "a+b+d+z2+z3" "a+b+z1+z2+z3" "a+c+d+z1+z2" "a+c+d+z1+z3"
#[111] "a+c+d+z2+z3" "a+c+z1+z2+z3" "a+d+z1+z2+z3" "b+c+d+z1+z2" "b+c+d+z1+z3"
#[116] "b+c+d+z2+z3" "b+c+z1+z2+z3" "b+d+z1+z2+z3" "c+d+z1+z2+z3" "a+b+c+d+z1+z2"
#[121] "a+b+c+d+z1+z3" "a+b+c+d+z2+z3" "a+b+c+z1+z2+z3" "a+b+d+z1+z2+z3" "a+c+d+z1+z2+z3"
#[126] "b+c+d+z1+z2+z3" "a+b+c+d+z1+z2+z3"

关于r - 提取列表元素并连接成 r 中的字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50425585/

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