gpt4 book ai didi

types - 理解类型注解中的类型变量

转载 作者:行者123 更新时间:2023-12-01 11:11:58 25 4
gpt4 key购买 nike

Elm docs像这样说明类型变量:

> List.reverse
<function> : List a -> List a

...the type variable a can vary depending on how List.reverse is used. But in this case, we have an a in the argument and in the result. This means that if you give a List Int you must get a List Int as well.

Maybe.map 的文档显示此注释:

map : (a -> b) -> Maybe a -> Maybe b

那么,当类型必须是同一类型时,为什么它们被注释为 ab
我希望 a 跟踪类型,即:

map : (a -> a) -> Maybe a -> Maybe a

最佳答案

So why are the types annotated as a and b when they must be the same type?

他们没有!如果 map 确实对输入参数类型和返回类型使用了相同的类型变量,它们会这样做,但是 map 可以从一种类型转换为另一种类型。这是一个具体的例子:

Maybe.map String.fromInt (Just 42)

String.fromInt 的类型为 Int -> String,我们将其用作 Maybe.map 的第一个参数。因此,如果我们尝试在 map 中替换它:

String.fromInt : (Int -> String)
Maybe.map : (a -> b ) -> Maybe a -> Maybe b

我们看到 Int 替换了 a 并且 String 替换了 b。因此 Maybe a 必须是 Maybe IntMaybe b 必须是 Maybe String。这意味着如果我们尝试给它一个 Maybe String 来代替:

Maybe.map String.fromInt (Just "foo")

我们会得到一个错误:

The 2nd argument to `map` is not what I expect:

1 | foo = Maybe.map String.fromInt (Just "foo")
^^^^^^^^^^
This `Just` call produces:

Maybe String

But `map` needs the 2nd argument to be:

Maybe Int

关于types - 理解类型注解中的类型变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59192273/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com