java - 随机发生器自动随机

Question

我们知道下面的代码是随机数

Random generator = new Random();
number = generator.nextInt(VALUE) + 1;

如果单击按钮，我会将这段代码添加到随机生成器

button1 = (Button)findViewById(R.id.buttonblack);
if(v==button1) {

 // Here, we are generating a random number
 Random generator = new Random();
 number = generator.nextInt(5) + 1; 
 // The '5' is the number of values

 // Here, we are checking to see what the output of the random was
 switch(number) { 

     case 1: if(bla.. bla.. bla.. == 1){
             //Do some blaa. blaa. blaa. logic
         }
        else if(bla.. bla.. bla.. == 2){
             //Do some blaa. blaa. blaa. logic
         }
         break;
       //and so on..

我的问题是如何使随机生成器方法每 2 秒自动随机一次，然后越来越快，而不是通过单击按钮

以及如何在单击某个按钮时随机停止，例如

buttonstop = (Button)findViewById(R.id.buttonstop);    
buttonstop.setOnClickListener(new View.OnClickListener() {

        public void onClick(View v){ 

            //Stop Random generator  

        }
     });

有人可以回答吗？谢谢

Answer 1

使用它，从 2 秒开始加快 20 毫秒

  private Handler mHandler = new Handler();
    int ms=2000; //2secs.
    Define a Runnable:

    private Runnable mUpdateTimeTask = new Runnable() {
        public void run() {
            // get random number here

        // You could do this call if you wanted it to be periodic:

    ms=ms-20; //20ms faster
            mHandler.postDelayed(this, ms);

            }
        };

    mHandler.postDelayed(mUpdateTimeTask, 100);