java - 当子字符串多于值时，将重复出现的子字符串替换为数组值

Question

public static String updatedStr()
{
    String [] ar= {"green","red","purple","black"};

    String str="The colors are (blue), (blue), and (yellow). I prefer (orange)";

    StringBuilder out = new StringBuilder ();
    int x = 0;
    int pos = 0;

    for(int i = str.indexOf('(', 0); i != -1; i = str.indexOf('(', i + 1)) {
        out.append (str.substring(pos,i)); // add the part between the last ) and the next (
        out.append (ar[x++]); // add replacement word
        pos = str.indexOf(')', i) + 1;
    }

    out.append (str.substring(pos)); // add the part after the final )
    return out.toString ();
}

我可以用字符串数组中的元素替换括号内的内容。

这里，我实现了输出

"The colors are green, red, and purple. I prefer black."

现在，我正在尝试实现一个场景String [] ar= {"green","re​​d"}。

我希望输出为

"The colors are green, red, and (yellow). I prefer (orange)."

如您所见，原始字符串的其余部分保持不变，因为没有足够的值来替换它们。

到目前为止，我已经尝试在 for 循环之前使用 while 循环来防止 ArrayIndexOutOfBoundsError，但实际上我仍然收到该错误。

Answer 1

您只需声明一个新变量来计算已进行的替换次数，并在达到数组长度时停止。

public static String updatedStr()
{
    String [] ar= {"green","red"};
    String str="The colors are (blue), (blue), and (yellow). I prefer (orange)";

    StringBuilder out = new StringBuilder ();
    int x = 0;
    int pos = 0;
    int added=0;
    for(int i = str.indexOf('(', 0); i != -1 && added<ar.length; i = str.indexOf('(', i + 1)) {
        out.append (str.substring(pos,i)); // add the part between the last ) and the next (
        out.append (ar[x++]); // add replacement word
        pos = str.indexOf(')', i) + 1;
    }
    out.append (str.substring(pos)); // add the part after the final )
    return out.toString ();
}