spring - 有没有更好的方法来配置 Bean？

Question

下面的Spring DI xml可以改进吗？ xml 下面是配置目标 bean 的编程方法。

<bean id="jacksonObjectMapper" class="org.codehaus.jackson.map.ObjectMapper" />
<bean id="jacksonSerializationConfig" class="org.codehaus.jackson.map.SerializationConfig"
    factory-bean="jacksonObjectMapper" factory-method="getSerializationConfig" />
<bean
    class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
    <property name="targetObject" ref="jacksonSerializationConfig" />
    <property name="targetMethod" value="setSerializationInclusion" />
    <property name="arguments">
        <list>
            <value type="org.codehaus.jackson.map.annotate.JsonSerialize.Inclusion">NON_NULL</value>
        </list>
    </property>
</bean>

ObjectMapper mapper = new ObjectMapper(); mapper.getSerializationConfig().setSerializationInclusion(JsonSerialize.Inclusion.NON_NULL);

Answer 1

XML 是执行此操作的一种非常糟糕的方法。是的，您可以这样做，但是编写一个配置您的ObjectMapper的FactoryBean要容易得多:

public class MyObjectMapperFactoryBean extends AbstractFactoryBean<ObjectMapper> {
   public Class<ObjectMapper> getObjectType() {
      return ObjectMapper.class;
   }

   public ObjectMapper createInstance() {
      // create and return ObjectMapper 
   }
}

然后在您的 XML 中:

<bean id="jacksonObjectMapper" class="x.y.MyObjectMapperFactoryBean" />